find all numbers > x and replace with y within a file Post: 302553400

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Top Forums Shell Programming and Scripting find all numbers > x and replace with y within a file Post 302553400 by durden_tyler on Wednesday 7th of September 2011 12:17:11 PM

09-07-2011

Registered User

Quote:

Originally Posted by herot

*UPDATE*
OK a change to what i need to alter:

Code:

4728.983333,AT1G54215,45.76,0,0,11.83,0,0,45.76,0,30.21,0,0,0,11.83,0,0,45.76,0,30.21,0,0,0
4289.164948,AT1G55670,66.73,0,24.76,0,0,0,66.73,0,11.83,0,8.75,24.76,0,0,66.73,0,11.83,0,8.75,0,0
4259.141414,AT2G32690,19.93,0,0,0,0,0,19.93,0,0,0,0,0,0,0,0,19.93,0,0,0,0,0
4199.354839,AT1G75550,54.09,54.09,0,11.83,0,0,31.62,0,0,0,0,0,11.83,0,0,31.62,0,0,0,0,0
4066.010753,AT2G34430,10.77,0,10.77,0,0,0,3.13,0,0,0,0,0,0,0,3.13,0,0,0,0,0,0

need to be converted to:

Code:

300,AT1G54215,45.76,0,0,11.83,0,0,45.76,0,30.21,0,0,0,11.83,0,0,45.76,0,30.21,0,0,0
300,AT1G55670,66.73,0,24.76,0,0,0,66.73,0,11.83,0,8.75,24.76,0,0,66.73,0,11.83,0,8.75,0,0
300,AT2G32690,19.93,0,0,0,0,0,19.93,0,0,0,0,0,0,0,0,19.93,0,0,0,0,0
300,AT1G75550,54.09,54.09,0,11.83,0,0,31.62,0,0,0,0,0,11.83,0,0,31.62,0,0,0,0,0
300,AT2G34430,10.77,0,10.77,0,0,0,3.13,0,0,0,0,0,0,0,3.13,0,0,0,0,0,0

so basically each value before ",AT" needs to be checked for > 300 and if so, then change to 300

Moderator's Comments:

Please use code tags!

I changed your sample data file a bit so that the test isn't skewed:

Code:

$
$ cat f17
4728.983333,AT1G54215,45.76,0,0,11.83,0,0,45.76,0,30.21,0,0,0,11.83,0,0,45.76,0,30.21,0,0,0
4289.164948,AT1G55670,66.73,0,24.76,0,0,0,66.73,0,11.83,0,8.75,24.76,0,0,66.73,0,11.83,0,8.75,0,0
259.141414,AT2G32690,19.93,0,0,0,0,0,19.93,0,0,0,0,0,0,0,0,19.93,0,0,0,0,0
4199.354839,AT1G75550,54.09,54.09,0,11.83,0,0,31.62,0,0,0,0,0,11.83,0,0,31.62,0,0,0,0,0
66.010753,AT2G34430,10.77,0,10.77,0,0,0,3.13,0,0,0,0,0,0,0,3.13,0,0,0,0,0,0
$
$
$ perl -lne '@x = split /,/;
             for ($i=0; $i<$#x; $i++) {$x[$i-1]=300 if $x[$i] =~ /^AT/ and $x[$i-1] > 300};
             print join ",",@x
            ' f17
300,AT1G54215,45.76,0,0,11.83,0,0,45.76,0,30.21,0,0,0,11.83,0,0,45.76,0,30.21,0,0,0
300,AT1G55670,66.73,0,24.76,0,0,0,66.73,0,11.83,0,8.75,24.76,0,0,66.73,0,11.83,0,8.75,0,0
259.141414,AT2G32690,19.93,0,0,0,0,0,19.93,0,0,0,0,0,0,0,0,19.93,0,0,0,0,0
300,AT1G75550,54.09,54.09,0,11.83,0,0,31.62,0,0,0,0,0,11.83,0,0,31.62,0,0,0,0,0
66.010753,AT2G34430,10.77,0,10.77,0,0,0,3.13,0,0,0,0,0,0,0,3.13,0,0,0,0,0,0
$
$

Quote:

Originally Posted by herot

How would I do this? How could i use <> symbols for numbers in the find/replace code below?

Code:
perl -pi -e 's/test/tst/'
OR is there a better way?

100 5000 2 432 4 2 33 4 5 6 65 300 301

needs to be:

100 300 2 300 4 2 33 4 5 6 65 300 300

also it might not always need spaces... i need multiple types of delimiters please.

Code:

$
$
$ echo "100 5000 2 432 4 2 33 4 5 6 65 300 301" | perl -ne 'while (/(\d+)/g) {print $1 > 300 ? 300 : $1," "} END{print "\n"}'
100 300 2 300 4 2 33 4 5 6 65 300 300
$
$

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