Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Find delimiter and double quote the field Post 302552893 by bartus11 on Tuesday 6th of September 2011 03:18:03 AM
Old 09-06-2011
Try:
Code:
perl -pe 's/[^*]+\*/$&"/;s/\*[^*]+$/"$&/' file

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

double-quote inside double-quote

hey all, i made a simple .sh like this: echo "<style media="screen" type="text/css">@import url("main.css");</style>" but the output is: <style media=screen type=text/css>@import url(main.css);</style> i want to keep double-quotes, can anyone help me? thanks (3 Replies)
Discussion started by: indraf
3 Replies

2. Shell Programming and Scripting

Multiple characters including single quote in delimiter

Hello, I need to replace the comma to something else between the single quote: 1aaa,bbb,'cc,cc','ddd',1 2aaa,bbb,'ccc','d,d',0 to 1aaa,bbb,'cc<comma>cc','ddd',1 2aaa,bbb,'ccc','d<comma>d',0 Can someone help? Thanks. (2 Replies)
Discussion started by: bgirl
2 Replies

3. Shell Programming and Scripting

Regex in grep to match all lines ending with a double quote (") OR a single quote (')

Hi, I've been trying to write a regex to use in egrep (in a shell script) that'll fetch the names of all the files that match a particular pattern. I expect to match the following line in a file: Name = "abc" The regex I'm using to match the same is: egrep -l '(^) *= *" ** *"$' /PATH_TO_SEARCH... (6 Replies)
Discussion started by: NanJ
6 Replies

4. Shell Programming and Scripting

how to find the nth field value in delimiter file in unix using awk

Hi All, I wanted to find 200th field value in delimiter file using awk.? awk '{print $200}' inputfile I am getting error message :- awk: The field 200 must be in the range 0 to 199. The source line number is 1. The error context is {print >>> $200 <<< } using... (4 Replies)
Discussion started by: Jairaj
4 Replies

5. Shell Programming and Scripting

double quote as the delimiter

I'm trying to extract a column from a csv file with either cut or awk but some of the fields contain comma with them: "Field1","Field2, additional info","Field3",...,"Field17",... If I want to extract column 3 and use comma as the delimiter, I'll actually get the additional info bit but not... (4 Replies)
Discussion started by: ivpz
4 Replies

6. Shell Programming and Scripting

Replace double quotes with a single quote within a double quoted string

Hi Froum. I have tried in vain to find a solution for this problem - I'm trying to replace any double quotes within a quoted string with a single quote, leaving everything else as is. I have the following data: Before: ... (32 Replies)
Discussion started by: pchang
32 Replies

7. Shell Programming and Scripting

Replacing Double Quote in Double Quote incsv file

Hi All , We have source data file as csv file and since data could contain commas ,each attribute is quoted into double quotes.However problem is that some of the attributa data also contain double quotes which is converted to double double quote while creating csv file XLs data : ... (2 Replies)
Discussion started by: Shalini Badal
2 Replies

8. Shell Programming and Scripting

Replacing all but the first and last double quote in a line with a single quote with awk

From: 1,2,3,4,5,This is a test 6,7,8,9,0,"This, is a test" 1,9,2,8,3,"This is a ""test""" 4,7,3,1,8,"""" To: 1,2,3,4,5,This is a test 6,7,8,9,0,"This; is a test" 1,9,2,8,3,"This is a ''test''" 4,7,3,1,8,"''"Is there an easy syntax I'm overlooking? There will always be an odd number... (5 Replies)
Discussion started by: Michael Stora
5 Replies

9. Shell Programming and Scripting

How can awk ignore the field delimiter like comma inside a field?

We have a csv file as mentioned below and the requirement is to change the date format in file as mentioned below. Current file (file.csv) ---------------------- empname,date_of_join,dept,date_of_resignation ram,08/09/2015,sales,21/06/2016 "akash,sahu",08/10/2015,IT,21/07/2016 ... (6 Replies)
Discussion started by: gopal.biswal
6 Replies

10. Shell Programming and Scripting

Need to split string on single quote as delimiter

I have a variable that contains the following string: FPATH=-rw-rw-r-- 1 user1 dba 0 Aug 7 13:14 /app/F11.3/app/cust/exe/filename1.exe' -rw-rw-r-- 1 user1 dba 0 Aug 19 10:09 /app/app/F11.3/app/cust/sql/33211.sql' -rw-r--r-- 1 user1 dba 0 Aug 6 17:20 /app/F11.2/app/01/mrt/file1.mrt' I... (7 Replies)
Discussion started by: mohtashims
7 Replies
URI::Find::Delimited(3pm)				User Contributed Perl Documentation				 URI::Find::Delimited(3pm)

NAME
URI::Find::Delimited - Find URIs which may be wrapped in enclosing delimiters. DESCRIPTION
Works like URI::Find, but is prepared for URIs in your text to be wrapped in a pair of delimiters and optionally have a title. This will be useful for processing text that already has some minimal markup in it, like bulletin board posts or wiki text. SYNOPSIS
my $finder = URI::Find::Delimited->new; my $text = "This is a [http://the.earth.li/ titled link]."; $finder->find($text); print $text; METHODS
new my $finder = URI::Find::Delimited->new( callback => &callback, delimiter_re => [ '[', ']' ], ignore_quoted => 1 # defaults to 0 ); All arguments are optional; defaults are provided (see below). Creates a new URI::Find::Delimited object. This object works similarly to a URI::Find object, but as well as just looking for URIs it is also aware of the concept of a wrapped, titled URI. These look something like [http://foo.com/ the foo website] where: * "[" is the opening delimiter * "]" is the closing delimiter * "http://foo.com/" is the URI * "the foo website" is the title * the URI and title are separated by spaces and/or tabs The URI::Find::Delimited object will extract each of these parts separately and pass them to your callback. callback "callback" is a function which is called on each URI found. It is passed five arguments: the opening delimiter (if found), the closing delimiter (if found), the URI, the title (if found), and any whitespace found between the URI and title. The return value of the callback will replace the original URI in the text. If you do not supply your own callback, the object will create a default one which will put your URIs in 'a href' tags using the URI for the target and the title for the link text. If no title is provided for a URI then the URI itself will be used as the title. If the delimiters aren't balanced (eg if the opening one is present but no closing one is found) then the URI is treated as not being wrapped. Note: the default callback will not remove the delimiters from the text. It should be simple enough to write your own callback to remove them, based on the one in the source, if that's what you want. In fact there's an example in this distribution, in "t/delimited.t". delimiter_re The "delimiter_re" parameter is optional. If you do supply it then it should be a ref to an array containing two regexes. It defaults to using single square brackets as the delimiters. Don't use capturing groupings "( )" in your delimiters or things will break. Use non-capturing "(?: )" instead. ignore_quoted If the "ignore_quoted" parameter is supplied and set to a true value, then any URIs immediately preceded with a double-quote char- acter will not be matched, ie your callback will not be executed for them and they'll be treated just as normal text. This is kinda lame but it's in here because I need to be able to ignore things like <img src="http://foo.com/bar.gif"> A better implementation may happen at some point. SEE ALSO
URI::Find. AUTHOR
Kake Pugh (kake@earth.li). COPYRIGHT
Copyright (C) 2003 Kake Pugh. All Rights Reserved. This module is free software; you can redistribute it and/or modify it under the same terms as Perl itself. CREDITS
Tim Bagot helped me stop faffing over the name, by pointing out that RFC 2396 Appendix E uses "delimited". Dave Hinton helped me fix the regex to make it work for delimited URIs with no title. Nick Cleaton helped me make "ignore_quoted" work. Some of the code was taken from URI::Find. perl v5.8.8 2008-03-01 URI::Find::Delimited(3pm)
All times are GMT -4. The time now is 04:40 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy