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UNIX for Dummies Questions & Answers
Delete directory from ghost owner with awk
Post 302548280 by macguy on Thursday 18th of August 2011 05:11:51 AM
08-18-2011
Quote:
These ghosts user users as you call them seem to be past defined users removed from the passwd file but where you chose NOt to remove their files... You should be able to extract all defined users and compare with the home directory (what is not in passwd is old and so you see the affected UID given at the time)
I'm not exactly sure how you mean now. I know, it's strange that when I delete an account in workgroup manager, the home directory for that user doesn't removes. So that is why I need a script to delete this numbered owners on the server.
I don't think I can do this on an easier way than to delete the user home directories with some script... But I need help do do this.
EDIT
This seems to be more difficult than I first thought. But I have some idea how to do this.
With this script ls -la | Awk '{print $3" "$9}' | grep '[0-9][0-9][0-9][0-9]'
I get this result:
5074 AbdMow1121
5248 AdaChr0814
5196 AdrLuk0908
1355 AgnBr02
5276 AgnHel0616
AgnMat0422 AgnMat0422
5274 AhmHas0101
AidHod0126 AidHod0126
5288 AidJac0313
1104 AleBe11
5242 AleBor1201
5265 AleFor0217
5019 AleHal0502
I'm very near my goal now, the only thing I want to do know is to filter the names from the first column like:
AgnMat0422
AidHod0126
AleNou1112
And so on...
Do someone know any possibility to only focus on the first column with grep so grep doesn't notice about the second column so I only need to type:
ls -la | Awk '{print $3" "$9}' | grep '[0-9][0-9][0-9][0-9]' But are only interested to grep $3 not the $9 column...
---------- Post updated at 09:11 AM ---------- Previous update was at 07:00 AM ----------
I solved the problem myself:
I was very near the solution but forget the ^ in the beginning of the grep syntax. Here is the code to delete this user directories:
Code:
for i in `ls -la | Awk '{print $3" "$9}' | grep '^[0-9][0-9][0-9][0-9]'` ; do rm -rf $i; done
Last edited by vbe; 08-18-2011 at 10:01 AM.. Reason: use code tags please for code and data
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LEARN ABOUT FREEBSD
logins
LOGINS(1) BSD General Commands Manual LOGINS(1) NAME
logins -- display account information SYNOPSIS
logins [-admopstux] [-g groups] [-l logins] DESCRIPTION
The logins utility displays information about user and system accounts. The following options are available: -a Display information about the password change and account expiration times for each account. -d Select accounts with duplicate UIDs. -g groups Select accounts that are members of the specified groups. If multiple group names are specified, they must be separated with com- mas. -l logins Select accounts matching the specified login names. If multiple names are specified, they must be separated with commas. -m Show information about secondary groups. -o Display the information for each account on a single line of colon-separated fields. -p Select accounts with no password. -s Select system accounts. These are currently defined as accounts with UIDs below 1000, plus the ``nobody'' account (UID 65534). -t Sort selected accounts by name rather than by UID. -u Select user accounts. These are currently defined as accounts with UIDs above 1000, except the ``nobody'' account (UID 65534). -x Display information about each account's home directory and shell. If multiple selection options are specified, all accounts matching any of the selection criteria will be displayed. If no selection options are specified, all accounts will be displayed. SEE ALSO
getgrent(3), getpwent(3), group(5), passwd(5), pw(8) HISTORY
The logins utility appeared in FreeBSD 4.10. AUTHORS
The logins utility was written by Dag-Erling Smorgrav <des@FreeBSD.org> based on similar utilities in other operating systems. BSD
March 6, 2004 BSD