Hi,
I have an expression using grep and nawk that captures the ID number of a given Unix process. It gets printed to screen but I don't know how to declare a variable to this returned value!
For example,
ps -ef|grep $project | grep -v grep | nawk '{print $2}'
This returns my number. How... (2 Replies)
I have a class with an integer pointer, which I have not initialized to NULL in the constructor. For example:
class myclass
{
private:
char * name;
int *site;
}
myclass:: myclass(....)
: name(NULL)
{
.....
}
other member function “delete “ the variable before... (2 Replies)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hello,
I am in following situation.-
COUNT=`ls -l | wc -l`
echo $COUNT
---> 26
NO_OF_FILES=$COUNT-1
echo $NO_OF_FILES
---> 26-1
Here, I want the output to be 25. How could I do this. It seems simple, but I am not getting it. Please help me. (2 Replies)
Hi !
I'm looking for a way to transform certain floating point numbers in a one-line, variable length file to integers.
I can do this in a crude way with sed :
sed -e 's/0\.\(\):/\1:/g' -e 's/0\.0\(\):/\1:/g' -e 's/1\.000:/100:/g' myfile ... but this doesn't handle the rounding correctly.
... (3 Replies)
I would like to know the maximum integer that a variable can hold. Actually one of my variable holds value 2231599773 and hence the script fails to process it.Do we have any other data type or options available to handle this long integers? (9 Replies)
I read 3 variables from from Inputfile.txt the third one "startnumber" is a number when i compare it with 9 ($startnumber -le 9) it give's me a "unary operator expected", i know that -le is for number comparison. What i need is to convert $startnumber to integer (i have try to do it with expr but... (8 Replies)
Hi Guys,
i guess there is a several ways to grub the strings from date and time
like THISMONTH='/bin/date +%m'
but the hard part is to add or sub that string to a variable
i tried to use let command
TWOMONTHSAGO=$THISMONTH
declare -i TWOMONTHSAGO
let TWOMONTHSAGO-=2
but there... (1 Reply)
Hi Folks -
Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64
I have a process that determines the start and end load periods for an Oracle data load process.
The variables used are as follows follows:
They are populated like such:
However, the load requires the month to be the... (11 Replies)
Discussion started by: SIMMS7400
11 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)