Delete files based on specific MMDDYYYY pattern in filename
Hi Unix gurus,
I am trying to remove the filenames based on MMDDYYYY in the physical name as such so that the directory always has the recent 3 files based on MMDDYYYY. "HHMM" is just dummy in this case. You wont have two files with different HHMM on the same day.
For example in a directory, I have files like
When I run the script it should delete the OPEN_INV_01012011_1345.xls and OPEN_INV_01012011_3456.txt
Note that the before the file extension, we always have "MMDDYYYY_HHMM"
I am using the following script:
This is what I am trying to do;
Any help is greatly appreciated.
Thanks
Last edited by Scott; 08-09-2011 at 01:04 PM..
Reason: Added code tags
I have one file which is having content as following...
0513468211,,,,20091208,084005,5,,2,3699310,
0206554475,,,,20090327,123634,85,,2,15615533
0206554475,,,,20090327,134431,554,,2,7246177
0103000300,,,,20090523,115501,89,,2,3869929
0736454328,,,,20091208,084005,75,,2,3699546... (7 Replies)
My files look like this
And I need to cut the sequences at the last "A" found in the following 'pattern' -highlighted for easier identification, the pattern is the actual file is not highlighted.
The expected result should look like this
Thus, all the sequences would end with AGCCCTA... (2 Replies)
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It's a tedious job to look through it, I'd like to remove those useless lines in it as there's a few thousands :
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32bm.txt:
249 253 A P - 0 0 8 0, 0.0 6,-1.4 0, 0.0 2,-0.4 -0.287 25.6-102.0 -74.4 161.1 37.1 13.3 10.9
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Hi all,
I am a newbie here. I have this requirement to find a file based on a pattern then return the filename if found.
I created a script based on online tutorials. Though, I am stuck & really appreciate if anyone can have a quick look & point me to the right direction?
#Script starts... (10 Replies)
Gents,
I am trying to delete all lines which start with "H" character, but keeping the fist header. Example In the input file I will delete all lines starting from line 8 which contents character "H" to the end of the file.
I try
sed '8,10000{/^H/d;}' file
But as don't know the end... (1 Reply)
BASH in Solaris 10
I have a log file like below. Whenever the pattern ORA-39083 is encountered, I want to delete the line which has this pattern and 3 lines below it.
$ cat someLogfile.txt
ORA-39083: Object type OBJECT_GRANT failed to create with error:
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Discussion started by: kraljic
4 Replies
LEARN ABOUT DEBIAN
gsf
GSF(1) GNOME GSF(1)NAME
gsf - archiving utility using the G Structured File library
SYNOPSIS
gsf [OPTION...] SUBCOMMAND ARCHIVE...
DESCRIPTION
This manual page briefly documents the gsf command.
gsf is a simple archive utility, somewhat similar to tar(1). It operates on files following one of the structured file formats understood
by the G Structured File library, for example, Microsoft Excel(TM) files.
OPTIONS
Options
-?, --help
Show help options
-v, --version
Display gsf's version
Subcommands
cat Output one or more files in archive
dump Dump one or more files in archive as formatted hexadecimal
help List subcommands
list List files in archive
props Archive list of property names
EXAMPLES
To list the content structure of a Microsoft Excel(TM) file arrays.xls:
gsf list arrays.xls
To dump Workbook, an individual data stream in arrays.xls:
gsf dump arrays.xls Workbook
AUTHORS
gsf's primary authors are Morten Welinder <terra@gnome.org> and Jody Goldberg <jody@gnome.org>.
The initial version of this manpage was written by J.H.M. Dassen (Ray) <jdassen@debian.org>.
SEE ALSO gnumeric(1)
The Gnumeric homepage <http://www.gnome.org/projects/gnumeric/>
The GNOME project page <http://www.gnome.org/>
gsf 29 November 2009 GSF(1)