You'll have to modify them a bit if you want to know what jar file each is in (and I assume that's something you'd want) as this will not give you that.
Hi,
I have this file which has 3 columns, District , stores and unit. What I want is all rows belonging to one district to be created separately under each district, the districts may vary every day , the source file may have 3 districts today and may have 160 tomorrow, so what I need is a... (20 Replies)
I need to find all the files that have group Read or Write permission or files that have user write permission.
This is what I have so far:
find . -exec ls -l {} \; | awk '/-...rw..w./ {print $1 " " $3 " " $4 " " $9}'
It shows me all files where group read = true, group write = true... (5 Replies)
I have a data file with records:
A123|Peter|20
A123|Jack |10
B222|Helen|15
B222|Jane |13
B222|Guy |30
I want for find the min for $3 group by $1.
i.e
A123|Jack|10
B222|Jane|13
Thanks. (4 Replies)
I've this file and need to sort the data in each group
File would look like this ...
cat file1.txt
Reason : ABC
12345-0023
32123-5400
32442-5333
Reason : DEF
42523-3453
23345-3311
Reason : HIJ
454553-0001
I would like to sort each group on the last 4 fileds and print them... (11 Replies)
Hello,
I need to repack a file inside several java archives (nested .jar files) with or without overwrite.
I am using a manual approach with mc, but it's painfully slow progress.
For example I want to refresh a file deep inside a java archive (with nested .jar files):
I have a java... (0 Replies)
Hi
I would like to search some data with awk and then print the last of the hits.
Find house and print last value
input:red house 4
blue boat 2
green house 6
black car 7
output:6
I now how to search using /house/, print third field print $3, an now I may use some form of $NR to get the... (3 Replies)
hi,
I want to create a volume group of 200 GB and then create different file systems on that.
please help me out. Its becomes confusing when the PP calculating PP.
I don't understand this concept. (2 Replies)
Hi,
I would like to know how to find our secondary group of user only.
I have used the command id -Gn user1
it is showing both groups of user.
Primary and secondary group. (2 Replies)
Hi All,
This discussion involves getting a way to load different jars in different Operating Systems.
Case Scenario
---------------
I am working on a specific OS known as NSK. Its an unix flavour and powers the HP NSK Servers. I am running one of my middleware app ( a java application) on... (3 Replies)
Discussion started by: Pabi
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)