How to Sort files based on predefined values.?
Normally Sorting happens for the alphabetic or numberic orders..
Is there any way to sort a fields based on the Field values..?
Field10 has :
one
two
three
five
four
six
ten
seven
eight
nine.
in predefined order { one, two, three,... (2 Replies)
Hi ,,
i have the below file...
D 2342135
B 214236
C argjlksd
V lskjrghaklsr
C slkrgj
B sdg4tsd
E aslkgjlkasg
i want to sort the lines into different files based on the starting letter of the line. so that i have different files for lines starting with a letter.
thanks (1 Reply)
Hi,
I am having trouble sorting one file based on another file. I tried the grep -f function and failed. Basically what I have is two files that look like this:
File 1 (the list)
gh
aba
for
hmm
File 2 ( the file that needs to be sorted)
aba 2 4 6 7
for 2 4 7 4
hmm 1 ... (3 Replies)
Hi
I have a requirement like below
I need to sort the files based on the timestamp in the file name and run them in sorted order and then archive all the files which are one day old to temp directory
My files looks like this
PGABOLTXML1D_201108121235.xml... (1 Reply)
Right now there is no unix direct commad that can sort the files base on its name having numbers:
We can use the following:
In case your file name are like:
abc-UP018.zip
xyz-UP019.zip
ls *|sort -t'-' -k2 (2 Replies)
Hi,
I have a list of log files as follows:
name_date_0001_ID0.log
name_date_0001_ID2.log
name_date_0001_ID1.log
name_date_0002_ID2.log
name_date_0004_ID0.log
name_date_0005_ID0.log
name_date_0021_ID0.log
name_date_0025_ID0.log
.......................................... (4 Replies)
Experts
I have a list of files in the directory
mysample1
mysample2
mysample3
mysample4
mysample5
mysample6
mysample7
mysample8
mysample9
mysample10
mysample11
mysample12
mysample13
mysample14
mysample15 (4 Replies)
I want to extract dates from the files and i have different types of files with pattern. I have list file with the patterns and want to date extract based on it in a sh script
Files in the directory :
file1_20160101.txt
file2_20160101_abc.txt
filexyz20160101.txt
list file with... (2 Replies)
I have the below input data in a file and need to get the output as mentioned below. Need to sort the data by size(Asc/des)/by subdirectory
Below is the input which is there in a file:
120 /root/path2/part-00000-d3700305-428d-4b13-8161-42051f4ac5ed-c000.json
532 ... (3 Replies)
Discussion started by: ajarramuk
3 Replies
LEARN ABOUT V7
join
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard
input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis-
carded.
These options are recognized:
-an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-e s Replace empty output fields by string s.
-jn m Join on the mth field of file n. If n is missing, use the mth field in each file.
-o list
Each output line comprises the fields specifed in list, each element of which has the form n.m, where n is a file number and m is a
field number.
-tc Use character c as a separator (tab character). Every appearance of c in a line is significant.
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort.
The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous.
JOIN(1)