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Top Forums UNIX for Dummies Questions & Answers Search filenames in directory, return filename only Post 302536918 by itkamaraj on Wednesday 6th of July 2011 12:56:48 PM
Old 07-06-2011
Code:
for i in `find . -type f | xargs grep -l test`; do basename $i; done > output.txt

The above command will give only the filename (not the absolute path from the current directory)

In the above command, i am grep the word "test"

check the output in the output.txt file
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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