07-04-2011
Thanks pludi.
but the problem is :
like the user "root" is being used by many users to login and i want to find that apart from me(current user ) who else have logged in with root.So just excluding the name of user doesn't help
.
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LEARN ABOUT CENTOS
pam_issue
PAM_ISSUE(8) Linux-PAM Manual PAM_ISSUE(8)
NAME
pam_issue - PAM module to add issue file to user prompt
SYNOPSIS
pam_issue.so [noesc] [issue=issue-file-name]
DESCRIPTION
pam_issue is a PAM module to prepend an issue file to the username prompt. It also by default parses escape codes in the issue file similar
to some common getty's (using x format).
Recognized escapes:
d
current day
l
name of this tty
m
machine architecture (uname -m)
machine's network node hostname (uname -n)
o
domain name of this system
release number of operating system (uname -r)
current time
s
operating system name (uname -s)
u
number of users currently logged in
U
same as u except it is suffixed with "user" or "users" (eg. "1 user" or "10 users")
v
operating system version and build date (uname -v)
OPTIONS
noesc
Turns off escape code parsing.
issue=issue-file-name
The file to output if not using the default.
MODULE TYPES PROVIDED
Only the auth module type is provided.
RETURN VALUES
PAM_BUF_ERR
Memory buffer error.
PAM_IGNORE
The prompt was already changed.
PAM_SERVICE_ERR
A service module error occurred.
PAM_SUCCESS
The new prompt was set successfully.
EXAMPLES
Add the following line to /etc/pam.d/login to set the user specific issue at login:
auth optional pam_issue.so issue=/etc/issue
SEE ALSO
pam.conf(5), pam.d(5), pam(8)
AUTHOR
pam_issue was written by Ben Collins <bcollins@debian.org>.
Linux-PAM Manual 09/19/2013 PAM_ISSUE(8)