Dividing a column by it's first number Post: 302533925

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Top Forums UNIX for Dummies Questions & Answers Dividing a column by it's first number Post 302533925 by cosmologist on Saturday 25th of June 2011 03:17:17 PM

06-25-2011

Registered User

Quote:

Originally Posted by bartus11

Try:

Code:

awk '$2&&!y{x=$2;y=1;next}y{print $2/x}' file

Thanks again for your help but ... it turns out that the columns that start with zero the are all zero (the whole column = 0 ).

So what I am trying to do now is to find a way to have "awk" look at column by column. If it has 0s then it creates a column that says "skip". If the values are non-zero then it divided that column by the first value. So for the example for the file:

Code:

671            9770.               0.               0.               0.               0.        11865563.        11944498.        11973309.        11995017.        12024223.        12047903.        12048693.
  672            9790.               0.               0.               0.               0.        11778218.        11856831.        11885525.        11907537.        11935052.        11960994.        11964138.
  673            9810.               0.               0.               0.               0.        11687964.        11765082.        11793659.        11815972.        11845333.        11869212.        11875084.
  674            9830.               0.               0.               0.               0.        11595616.        11666963.        11692695.        11713748.        11740650.        11756244.        11771060.
  675            9850.               0.               0.               0.               0.        11516347.        11589346.        11614196.        11632058.        11654579.        11661568.        11672441.
  676            9870.               0.               0.               0.               0.        11441105.        11509168.        11533144.        11551707.        11574523.        11576457.        11581097.
  677            9890.               0.               0.               0.               0.        11332098.        11392952.        11410284.        11422224.        11436475.        11435705.        11435705.
  678            9910.               0.               0.               0.               0.        11289472.        11356219.        11379235.        11394963.        11397649.        11401868.        11391511.
  679            9930.               0.               0.               0.               0.        11205454.        11267730.        11286069.        11299059.        11293328.        11289889.        11268112.
  680            9950.               0.               0.               0.               0.        11130010.        11194699.        11214867.        11211443.        11211062.        11192036.        11145612.

it would list the first column, the second, and then for the third column it would print "skip" the same for columns 4,5 and 6 then it would divide column 7 by 11865563. and column 8 by 11944498. ... etc

Is that possible?

cosmologist

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db2_field_display_size

DB2_FIELD_DISPLAY_SIZE(3)						 1						 DB2_FIELD_DISPLAY_SIZE(3)

db2_field_display_size - Returns the maximum number of bytes required to display a column

SYNOPSIS

       int db2_field_display_size (resource  $stmt, mixed  $column)

DESCRIPTION

	Returns the maximum number of bytes required to display a column in a result set.

PARAMETERS

	      o $stmt
		- Specifies a statement resource containing a result set.

	      o $column
		-  Specifies  the  column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
		string containing the name of the column.

RETURN VALUES

	Returns an integer value with the maximum number of bytes required to display the specified column. If the column does not  exist  in  the
       result set, db2_field_display_size(3) returns FALSE.

SEE ALSO

       db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3).

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