hi
I have the below code to convert hexa to binary. It is working fine, but i want to store the binary in char or int. The below program is printing the result.
Code:
void ConvertHexToBinary(char sHexValue[])
{
int i;
printf("Binary Equivalent=");
for(i=0;sHexValue[i]!=NULL;i++)
{
switch(sHexValue[i])
{
case '0':
printf("0000");
break;
case '1':
printf("0001");
break;
case '2':
printf("0010");
break;
case '3':
printf("0011");
break;
case '4':
printf("0100");
break;
case '5':
printf("0101");
break;
case '6':
printf("0110");
break;
case '7':
printf("0111");
break;
case '8':
printf("1000");
break;
case '9':
printf("1001");
break;
case 'a':
case 'A':
printf("1010");
break;
case 'b':
case 'B':
printf("1011");
break;
case 'c':
case 'C':
printf("1100");
break;
case 'd':
case 'D':
printf("1101");
break;
case 'e':
case 'E':
printf("1110");
break;
case 'f':
case 'F':
printf("1111");
break;
default:
printf("\nEntered number is not Hexadecimal. Printed value is incorrect. ");
break;
}
}
}
void main()
{
char s[128]= cpSegment;
printf("\n\n\nBinary equivalent of primary segment is: ");
ConvertHexToBinary(s);
// Here i want to get binary in int or char like this
//char or int = ConvertHexToBinary(s);
}
thanks
Moderator's Comments:
Please use less formatting, code tags and indent code. Thanks
Last edited by Scott; 05-29-2011 at 09:16 AM..
Reason: Code tags, etc.
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LEARN ABOUT SUSE
etext
END(3) Linux Programmer's Manual END(3)NAME
etext, edata, end - end of program segments
SYNOPSIS
extern etext;
extern edata;
extern end;
DESCRIPTION
The addresses of these symbols indicate the end of various program segments:
etext This is the first address past the end of the text segment (the program code).
edata This is the first address past the end of the initialized data segment.
end This is the first address past the end of the uninitialized data segment (also known as the BSS segment).
CONFORMING TO
Although these symbols have long been provided on most Unix systems, they are not standardized; use with caution.
NOTES
The program must explicitly declare these symbols; they are not defined in any header file.
On some systems the names of these symbols are preceded by underscores, thus: _etext, _edata, and _end. These symbols are also defined for
programs compiled on Linux.
At the start of program execution, the program break will be somewhere near &end (perhaps at the start of the following page). However,
the break will change as memory is allocated via brk(2) or malloc(3). Use sbrk(2) with an argument of zero to find the current value of
the program break.
EXAMPLE
When run, the program below produces output such as the following:
$ ./a.out
First address past:
program text (etext) 0x8048568
initialized data (edata) 0x804a01c
uninitialized data (end) 0x804a024
Program source
#include <stdio.h>
#include <stdlib.h>
extern char etext, edata, end; /* The symbols must have some type,
or "gcc -Wall" complains */
int
main(int argc, char *argv[])
{
printf("First address past:
");
printf(" program text (etext) %10p
", &etext);
printf(" initialized data (edata) %10p
", &edata);
printf(" uninitialized data (end) %10p
", &end);
exit(EXIT_SUCCESS);
}
SEE ALSO objdump(1), readelf(1), sbrk(2), elf(5)COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
GNU 2008-07-17 END(3)
05-29-2011
