I am converting mainframes JCL to be used in shell on a one to one basis... when i use the sort command unix does ascii sort as a result which numbers are first followed by charecters in the Ascending sort ... but themainframes uses the EBCDIC as result gives the charecters followed by numbers in... (5 Replies)
My shell script below for import data to Oracle
it run okay. but the text display not correct follow order command executed.
=========================Shell Script code=================
#!/bin/sh
#directory = ${1-'pwd'}
#run import data with SQLLoader
runSQLLoader()
{
... (2 Replies)
I need to sort the particular column only in reverse order how i can give it..
if i give the -r option the whole file is getting sorted in reverse order.
1st 2nd col 3rd
C col 4th col 5th col
-------------------------------------------
C... (7 Replies)
Hi
I am using this
cat substitutionFeats.txt | gawk '{$0=gensub(/\t/,"blabla",1);print}' | gawk '{print length, $0}' | sort -n | sort -r
and the "sort -n" command doesn't work as expected: it leads to a wrong ordering:
64 Adjustable cuffs
64 Abrasion-
64 Abrasion pas
647 Sanitized 647... (4 Replies)
Hello all
I was wondering if someone has an idea how to sort by a specific order, let's say by a specific alphabet containing only 4 letters like (d,s,a,p) instead of (a,b,c....z) ??
Cheers! (6 Replies)
Hi,
while using following awk commend I’m getting confused,
The output is not like as the row present in input files, can anyone explain and tell me how to print in the order like in input.
value=$(awk 'FNR>1 && NR==FNR{a=$4;next} a{sum+=$4} END {for(i in sum){printf i"\t"sum/2"@@";}}'... (5 Replies)
I am trying to sort a log file in chronological order to identify which ones did not process and still have an old (probably yesterday's) date. This is a sample of the file:flatf 010140 flatf Thu May 10 22:22:11 CST 2018 flats finished
flatf 010142 flatf Thu May 10 22:31:25 CST 2018 flats... (4 Replies)
Hi,
I have a problem . I have few directories like inpTDT_1, inpTDT_2, inpTDT_3 and so on inside HOME directory . In one of my perl script (which is in my HOME), the above directories like inpTDT_1, inpTDT_2, inpTDT_3 are sorting out in an order So I wanted to sort all the inpTDT_1, inpTDT_2,... (1 Reply)
Discussion started by: venkatesh
1 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)