What language is the file from which you are removing comments? The fact that you say it has "echo" statements makes me think "shell", but shells do not support "/*....*/" style comments.
Regardless of language, it's quite a leap to say that's it's obvious that comments containing "echo" should be retained. If you were told to remove all comments then that it what you should do. Maybe you should clarify your instructions.
I haven't tried it, but the first sed script you posted looks like it should work. It's pretty clever actually. But you can't split it up into separate sed statements. It's a unit and it needs to stay that way.
/\/\*/!b Loop until we find a line with "/*" in it. Once we find such a line we can proceed to the the rest of the sed script.
Code:
:x
/\*\//!{
N
bx
}
This little paragraph asks if we have a "*/". We might if the earlier sed statement found a one line comment. But if the comment extends to several lines, we will not immediately have the terminating "*/". So read read another input line with the "N" command. The "bx" jumps back to the ":x". That is how we loop in sed. Eventually we will read the "*/" and fall out of the loop to the final statement.
Code:
# delete /*...*/
s/\/\*.*\*\///
The comment is correct. It deletes the "/*...*/" comment. If all you have is one line comments, this one command may be all you need.
I have not tested it. But it all looks good. But each statement depends on the others. You are not going to be able to turn this sed script into several sed scripts. I hope this helps you.
Hello Unix Gurus,
We are doing large system upgrade. We expect upgrade to last 180-200 hours. The servers are located remotely.
I am looking for solution which allows me to reconnect to the same session active on unix server where I launched the process. This would protect from local client... (0 Replies)
I have a file with a single line in it as below.
field1 field2 field3
Different fields separated by spaces. I need the output as below.
field1
field2
field3
Any sed/awk solution you can suggest? (6 Replies)
$db2 connection ...........Q
a=`$db2 -x "select A from tablename where z in (select z from tablename Q where condition fetch first 1 rows only ) with ur"`
b=`$db2 -x "select B from tablename where z in (select z from tablename Q where condition fetch first 1 rows only) with ur"`
$db2... (2 Replies)
hi
i have one file where i want to substitute only first instance of
swap
with swap1
i want to replcae only first instance of swap in my script
i know we can do this with awk. but i need to do this with sed only
i tried follwoing code
sed 's/swap/swap1' filename
but here all... (15 Replies)
Hi,
can anyone help me with my scrip please. I wanted do following tasks:
1. List all the directory
2. A STDIN to ask user to enter a directory name from listed directories
3. command to check if the directory exists( or a command to validate if the user entered a valid directory name)
... (2 Replies)
Hi All,
I am using LATEX and need to delete all the lines in a file matching:
\begin{work}
I know there are several ways to do this, but I am trying to do it with the substitute command in VI. The problem is I can't get substitute to recognize the character '\'!
How do I do it?
... (7 Replies)
have this code but when i run it i get this error
./pulse: line 2: and here is the code
#!/bin/bash
if ;
then
pulseaudio -k;
fi
what am i doing wrong
thanks
Adam (5 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Try running 'phone4 xyz' and see what happens.
Modify your program so that if no matching name is found, an... (1 Reply)
Hello people,
I am having problem to sort, sed and zero padding of column in csv file.
7th column only.
Input of csv file:
1,2,3,4,5,6,4/1/2010 12:00 AM,8
1,2,3,4,5,6,3/11/2010 9:39 AM,8
1,2,3,4,5,6,5/12/2011 3:43 PM,8
1,2,3,4,5,6,12/20/2009 7:23 PM,8
Output:... (5 Replies)
I'm trying to remove '--X' from the whole file and using variables replace $oldvar with $newvar.
I have tried with double quotes but it doesn't seem to work. $newvar is set to /usr/bin/bash. Would appreciate some guidance.
newvar=$(which bash)
oldvar=/bin/bash
sed... (1 Reply)
Discussion started by: itman73
1 Replies
LEARN ABOUT CENTOS
bashbug-64
BASHBUG(1) General Commands Manual BASHBUG(1)NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--version] [--help] [email-address]
DESCRIPTION
bashbug is a shell script to help the user compose and mail bug reports concerning bash in a standard format. bashbug invokes the editor
specified by the environment variable EDITOR on a temporary copy of the bug report format outline. The user must fill in the appropriate
fields and exit the editor. bashbug then mails the completed report to bug-bash@gnu.org, or email-address. If the report cannot be
mailed, it is saved in the file dead.bashbug in the invoking user's home directory.
The bug report format outline consists of several sections. The first section provides information about the machine, operating system,
the bash version, and the compilation environment. The second section should be filled in with a description of the bug. The third sec-
tion should be a description of how to reproduce the bug. The optional fourth section is for a proposed fix. Fixes are encouraged.
ENVIRONMENT
bashbug will utilize the following environment variables if they exist:
EDITOR Specifies the preferred editor. If EDITOR is not set, bashbug defaults to emacs.
HOME Directory in which the failed bug report is saved if the mail fails.
TMPDIR Directory in which to create temporary files and directories.
SEE ALSO bash(1)AUTHORS
Brian Fox, Free Software Foundation
bfox@gnu.org
Chet Ramey, Case Western Reserve University
chet@po.cwru.edu
GNU Bash-4.0 1998 July 30 BASHBUG(1)