This suggested command contains design and implementation errors. Consider what happens on April 1st. The grep match string becomes "Apr01" which will not match a directory list.
A less-than-perfect way of picking up files and directories created today is to match against the date and check that there is a colon character somewhere on the line.
The importance here is to get the "date" command right and to preserve spaces in the date throughout by proper use of double quote characters.
Beware of dates with a single digit day. The command "date +%d" which is wrongly advised in various earlier posts gives the day of the month with a leading zero but "ls -lar" give the day of the month with a leading space. Therefore we must use "date +%e" and preserve that space character.
My example is not a recommended method (mainly because it does not work with filenames containing colon characters and is awkward with filenames containing space characters). My earlier post in this thread is a recommended method.
I have task in which I need to pickup a set of files from a directory
depending on the following criteria:
Every month 6 files are expected to arrive at /test.
The files come with date timestamp and the latest file set for the month needs to be used
Suppose this is the set of files that present... (5 Replies)
Hi,
I have some list of directories in the form datemonthyear e.g. 02082009, 03082009 and 04082009 etc.
I need to pick the latest directory from the current working directory.
Outcome:
05082009
This is the output am expecting.
Thanks (6 Replies)
Hi,
I am new to unix and shell scripting,can anybody help me in sctipting a requirement.
my requirement is to get the latest directory the name of the directory will be like CSB.monthdate_time stamp
like CSB.Sep29_11:16 and CSB.Oct01_16:21.
i need to pick the latest directory.
in the... (15 Replies)
Hi
In my script i am trying to access mainframe server using FTP,
in the server i have filee with the timestamp.I need to get the file with the latest timestamp among them . The server has the below files
/
ftp> cd /outbox
250 CWD command successful
ftp> ls
200 PORT command successful... (4 Replies)
Hi
I have a requirement like below
I need to sort the files based on the timestamp in the file name and run them in sorted order and then archive all the files which are one day old to temp directory
My files looks like this
PGABOLTXML1D_201108121235.xml... (1 Reply)
Hi Friends,
Newbie to shell scripting. Currently i have used the below to sort data based on filenames and datestamp
$ printf '%s\n' *.dat* | sort -t. -k3,4
filename_1.dat.20120430.Z
filename_2.dat.20120430.Z
filename_3.dat.20120430.Z
filename_1.dat.20120501.Z
filename_2.dat.20120501.Z... (1 Reply)
Hi Friends,
Newbie to shell scripting
Currently i have used the below to sort data based on filenames and datestamp
$ printf '%s\n' *.dat* | sort -t. -k3,4
filename_1.dat.20120430.Z
filename_2.dat.20120430.Z
filename_3.dat.20120430.Z
filename_1.dat.20120501.Z
filename_2.dat.20120501.Z... (12 Replies)
Hi ,
I did the initial search but could not find what I was expecting for.
15606Always_9999999997_20160418.xml
15606Always_9999999998_20160418.xml
15606Always_9999999999_20160418.xml
9819Always_99999999900_20160418.xml
9819Always_99999999911_20160418.xmlAbove is the list of files I... (4 Replies)
Hi All,
I have list of files like below with name abcxyz.timestamp. I need a unix command to pick the latest file from the list of below files. Here in this case the lates file is abcxyz.20190304103200. I have used this unix command "ls abcxyz*|tail -1" but i heard that it is not the appropriate... (2 Replies)
Discussion started by: rakeshp
2 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)