Sponsored Content
Full Discussion: looping in awk
Top Forums Shell Programming and Scripting looping in awk Post 302522694 by euval on Monday 16th of May 2011 10:35:08 AM
Old 05-16-2011
looping in awk

How do I remove last comma?
Code:
echo "xx yy zz" | awk 'BEGIN{FS=" "}{for (i=1; i<=NF; i++) printf "%s,", $i}'

output:
Code:
xx,yy,zz,

required output:
Code:
xx,yy,zz

or (ideally!):
Code:
xx, yy & zz

many thanks in advance!
 

10 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

Looping in awk

Can somebody give me a cleaner way of writing the following script. I was thinking that I could use a loop in the awk statement. It works fine the way it is but I just want the script to be cleaner. #!/usr/bin/sh for r in 0 1 2 3 4 5 6 do DAY=`gdate --date="${r} days ago" +%m\/%d\/%y`... (3 Replies)
Discussion started by: keelba
3 Replies

2. Shell Programming and Scripting

Awk: looping problem!

I am having a problem with awk when I run it with a loop. It works perfectly when I echo a single line from the commandline. For example: echo 'MFG009 9153852832' | awk '$2 ~ /^0-9]$/{print $2}' The Awk command above will print field 2 if field 2 matches 10 digits, but when I run the loop... (5 Replies)
Discussion started by: cstovall
5 Replies

3. Shell Programming and Scripting

looping and awk/sed help

I am pretty new to this, but imagine what I am trying to do is possible iI am trying to make an automated DB comparison tool that selects all columns in all tables and compares them to the same thing in another DB. anyway I have created 2 files to help with this the first file is a... (13 Replies)
Discussion started by: Zelp
13 Replies

4. Shell Programming and Scripting

Urgent - Looping using AWK

Hi I have a file which is having following text. The file is in a tabular form with 5 fields. i.e field1, field2 ..... field5 are its columns and there are many rows in it say COUNT is the number of rows Field 1 Field2 Field3 Field4 Field5 ------- ------- ... (8 Replies)
Discussion started by: skyineyes
8 Replies

5. UNIX for Dummies Questions & Answers

Help with AWK looping

I'm trying to parse a configuration text file using awk. The following is a sample from the file I'm searching. I can retrieve the formula and recipe names easily but now I want to take it one step farther. In addition to the formula name, I would like to also get the value of the attribute... (6 Replies)
Discussion started by: new2awk
6 Replies

6. Shell Programming and Scripting

Looping within the elements of a file using awk

Hi all, I have a file containing 5000 rows and 4 columns. I need to do a loop within the rows based on the values of column 3. my sample data is formatted like the ones below: what i need to do is to make a loop that will allow me to plot the values of x,y,values corresponding to month 1 to month... (10 Replies)
Discussion started by: ida1215
10 Replies

7. Shell Programming and Scripting

AWK looping over 2 variables

I would like to loop over variables i and j consecutively, { a = -6.7 b = 7.0 c =0.1 { for (i = 0; i<=(b-a)/c; i++) for (j = 1; j<=(b-a)/c; j++) '$1<=(a+j*c)&&$1>=(a+i*c)' FILENAME > output_j '{print $2}' output_j > output_j_f } I essentially want to print the range of $1... (9 Replies)
Discussion started by: chrisjorg
9 Replies

8. Shell Programming and Scripting

Looping through pairs of files with awk

Hi all, please help me construct the command. i want to loop through all files named bam* and bed*. My awk works for a particular pair but there are too many pairs to do manually. I have generated multiple files in a folder in a given pattern. The files are named like bam_fixed1.bam... (2 Replies)
Discussion started by: newbie83
2 Replies

9. Shell Programming and Scripting

Help on looping using awk

I have the data like this: PONUMBER,SUPPLIER,LINEITEM,SPLITLINE,LINEAMOUNT,CURRENCY IR5555,Supplier1,1,1,83.1,USD IR5555,Supplier1,1,3,40.4,USD IR5555,Supplier1,1,6,54.1,USD IR5555,Supplier1,1,8,75.1,USD IR5556,Supplier2,1,1,41.1,USD IR5556,Supplier2,1,3,43.1,USD ... (3 Replies)
Discussion started by: jeffreybsu
3 Replies

10. Shell Programming and Scripting

awk nested looping?

I am trying to parse a text file and send its output to another file but I am having trouble conceptualizing how I am supposed to do this in awk. The text file has a organization like so: Name Date Status Location (city, state, zip fields) Where each of these is on a separate line in... (1 Reply)
Discussion started by: kellyanneghj
1 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 07:01 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy