Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: MEMO: Issue with a for loop
Top Forums Shell Programming and Scripting MEMO: Issue with a for loop Post 302521550 by mrn6430 on Wednesday 11th of May 2011 02:54:11 PM
Old 05-11-2011
Fixed the first issue, But the echo PID line is not displaying the result of the lsof command: it is display this line 8 times:
PID = spaces
 

8 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

loop issue

I have 2 files one of them has all the all mac addresses and the other one has all the ip addresses. Basically, I want to loop thru those 2 files and generate a configuration like below: host www184.domain.com { hardware ethernet 00:13:72:3B:B4:3A; fixed-address 192.168.0.184; }... (4 Replies)
Discussion started by: kkkk
4 Replies

2. Shell Programming and Scripting

issue with for loop

Hi All, Please help me with for loop!!!! I have to put the limit with for loop like For I in 1..30 Do Echo $i Done I want my output to be like 1 2 3 4 5 6 7 8 9 till 30 (6 Replies)
Discussion started by: kumarmani
6 Replies

3. Programming

Airport using semaphores and shared memo

Hi just doin' this here for the naval school, back here in Pportugal, and needed some help, especially with the shared memo i want to use for the 10 airport gate, and the maximum of 4 planes preparing to leave; canīt figure out how the gate can be id by the same PID. WELL, if someone wants to... (1 Reply)
Discussion started by: Turbo
1 Replies

4. Homework & Coursework Questions

Airport using semaphores and shared memo

Hi just doin' this here for the naval school, back here in Pportugal, and needed some help, especially with the shared memo i want to use for the 10 airport gate, and the maximum of 4 planes preparing to leave; canīt figure out how the gate can be id by the same PID. WELL, if someone wants to... (2 Replies)
Discussion started by: Turbo
2 Replies

5. Linux

HOW CAN I PRINT OUT THE MEMO ONLY?

I tried to print out external memo in LINUX system, however, each time in the print out also print out M--. M--. in front of the external memo, my question is HOW CAN I PRINT OUT THE MEMO ONLY? THANKS (0 Replies)
Discussion started by: scottblee
0 Replies

6. Shell Programming and Scripting

Issue with while loop?

Hi, I have prepared a script to search for backup file information on the Linux server. Script works fine for the most part except the echo statement inside an IF conditional block displays the message ''snapshot directory not found on xxxxx" even though the .snapshot directory is found a... (11 Replies)
Discussion started by: svajhala
11 Replies

7. Shell Programming and Scripting

Issue with for loop

Hi Team, I have for loop in my shell script. Which basically loop through all files in the directory, When some files are in the directory it works just fine. But if there are no files at all..still the for loop try to execute. Please help. Below is the code. #!/bin/ksh echo "Program... (5 Replies)
Discussion started by: bharath561989
5 Replies

8. UNIX for Beginners Questions & Answers

Issue when doing a loop

Hi, I just have started learning shell scripting (sh). Why do i only get the date? while read dt do echo "Date : ${dt} sed -n '/${dt}/,/${dt}/p' file1.log | grep -w ERROR done < date1.dat INPUT - date1.dat 2019-04-05 04:58:25 2019-04-05 04:58:26 2019-04-05 05:00:56... (3 Replies)
Discussion started by: margel
3 Replies

LEARN ABOUT XFREE86

pldd

PLDD(1) 							 Linux User Manual							   PLDD(1)

NAME

       pldd - display dynamic shared objects linked into a process

SYNOPSIS

       pldd pid
       pldd option

DESCRIPTION

       The  pldd  command  displays a list of the dynamic shared objects that are linked into the process with the specified process ID.  The list
       includes the libraries that have been dynamically loaded using dlopen(3).

OPTIONS

       -?, --help
	      Display program help message.

       --usage
	      Display a short usage message.

       -V, --version
	      Display the program version.

EXIT STATUS

       On success, pldd exits with the status 0.  If the specified process does not exist, the user does not have permission to access its dynamic
       shared  object  list, or no command-line arguments are supplied, pldd exists with a status of 1.  If given an invalid option, it exits with
       the status 64.

VERSIONS

       pldd is available since glibc 2.15.

CONFORMING TO

       The pldd command is not specified by POSIX.1.  Some other systems have a similar command.

NOTES

       The command

	   lsof -p PID

       also shows output that includes the dynamic shared objects that are linked into a process.

       The gdb(1) info shared command also shows the shared libraries being used by a process, so that one can obtain similar output to pldd using
       a command such as the following (to monitor the process with the specified pid):

	   $ gdb -ex "set confirm off" -ex "set height 0" -ex "info shared" 
		   -ex "quit" -p $pid | grep '^0x.*0x'

BUGS

       Since glibc 2.19, pldd is broken: it just hangs when executed.  It is unclear if it will ever be fixed.

EXAMPLE

       $ echo $$	       # Display PID of shell
       1143
       $ pldd $$	       # Display DSOs linked into the shell
       1143:	 /usr/bin/bash
       linux-vdso.so.1
       /lib64/libtinfo.so.5
       /lib64/libdl.so.2
       /lib64/libc.so.6
       /lib64/ld-linux-x86-64.so.2
       /lib64/libnss_files.so.2

SEE ALSO

       ldd(1), lsof(1), dlopen(3), ld.so(8)

COLOPHON

       This  page is part of release 4.15 of the Linux man-pages project.  A description of the project, information about reporting bugs, and the
       latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.

GNU
								    2017-09-15								   PLDD(1)
All times are GMT -4. The time now is 02:12 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy