05-11-2011
'for loop' problem!
Hi,
I'm trying to run a process on a load of data. The data is labelled as:
con_3194
con_3367
con_3173
con_3188
etc. (there are about 80 of these files).
And I'm trying to run a process called 'fslswapdim' so this process runs on all the files! Currently, I'm processing each file alone by doing:
fslswapdim con_3194 -z -x y con_3194_swapdim
fslswapdim con_3367 -z -x y con_3367_swapdim
But I would like to learn how to make a loop so they all can be processed at once.
Can anybody help me do this please? I think it's something like
for i in con_* ; do fslswapdim -z -x y con_$i_swapdim; done;
Everything I'm trying is wrong!
Thank you!
10 More Discussions You Might Find Interesting
1. Programming
hi all,
i have written the following code:
while(proceed !='Y' && proceed!='N' && proceed!='y' && proceed!='n')
{
printf("\nPress \n\t 'Y' or 'y' to continue \n\t 'N' or 'n' to cancel:");
scanf("%c",&proceed);
}
the output i am gettin is:
Press
'Y' to continue
... (1 Reply)
Discussion started by: mridula
1 Replies
2. Shell Programming and Scripting
Hi,
I have a directory called logs in which i have the log files.
i have to touch the file before deleting it.
i am doing like this
filestodelete="*.log* *log*"
for files in $filestodelete
do
touch $files $files.$(date +%a)
rm -f $filestodelete
done
touch is not working... (5 Replies)
Discussion started by: namishtiwari
5 Replies
3. UNIX for Advanced & Expert Users
Hi guys my while do loop is not working properly;
As soon as the load_date and run_date is same it should stop can somebody tell me where I am having the problem?
In an oracle table I have
LOAD_DT=5/1/2009 DATE datatype
RUN_DT=5/5/2009 DATE datatype
Now in a script with a spool file I get the... (15 Replies)
Discussion started by: henrysmith
15 Replies
4. Shell Programming and Scripting
Hi Guys,
This is my code.. I am getting an error in the inside while statement when comparing.. I am not able to figure it out.. Pls help me...
while read value fatherid son_id top_id r_type
do
inside_value=1;
echo $inside_value;
echo $r_type;
while
do
echo... (6 Replies)
Discussion started by: mac4rfree
6 Replies
5. Shell Programming and Scripting
hi
I had created a while loop in a script file called whiletest.sh as follows
as follows:
count=0
max=10
while
do
echo $count
echo count=$(count+1)" "
done
echo "value of count:$count"
then i run the script with the command
sh whilestest.sh
but its giving me an error... (5 Replies)
Discussion started by: angel12345
5 Replies
6. UNIX for Dummies Questions & Answers
I have a while loop with -f and -o option.Can any one please tell me what that stands for?The Sample code is as follows:-
while
do
## some processing
done (10 Replies)
Discussion started by: Param0073
10 Replies
7. Shell Programming and Scripting
Hi Script Gurus,
I am facing issue with while loop in bash. The while loop is running as end less loop even after given criteria does not meet.
STATE_BEFORE_SPLIT () {
for clone in $Clonegroups; do
state=$( $Navicmd -listclone -name $clone -cloneid $Cloneid |awk... (3 Replies)
Discussion started by: RobP
3 Replies
8. Shell Programming and Scripting
Hi,
I work on Ab-initio ETL tool which is based on Unix. I made a small script which has two loop's one with in another. All the functionality is working for the first line of outer loop but when it comes to other lines of outer loop it is throwing error as command not found. Below is the... (4 Replies)
Discussion started by: Ravindra Swan
4 Replies
9. Shell Programming and Scripting
I am trying to do a while do loop that asks for a password and returns if the password entered is incorrect. I have that part working however i want to modify it so that if a similar word is entered it will read "that is close but incorrect" and i cannot seem to get it working, being new in the... (6 Replies)
Discussion started by: lm5522
6 Replies
10. Shell Programming and Scripting
Hi all,
a problem with a loop. Imagine it starts with
var1="$(cat txtif.out )"while
do
echo file1
echo file2
echo y > txtif.out
if
then
break
fi
done
exit 0
the problem is that if the file is changing during the loop seems to continue as it reads "x" state,... (5 Replies)
Discussion started by: Board27
5 Replies
LEARN ABOUT DEBIAN
speedy_backend
SPEEDY_BACKEND(1p) SPEEDY_BACKEND(1p)
NAME
speedy_backend - the backend process for a persistent Perl interpreter
SYNOPSIS
none ; this program is not meant to be called directly.
DESCRIPTION
speedy, short for SpeedyCGI, is a way to run perl scripts persistently, which can make them run much more quickly.
After the script is initially run, instead of exiting, the perl interpreter is kept running inside a backend process, speedy_backend. Dur-
ing subsequent runs, this interpreter is used to handle new executions instead of starting a new perl interpreter each time. A very fast
frontend program, speedy, written in C, is executed for each request. This fast frontend then contacts the persistent Perl process, which
is usually already running, to do the work and return the results.
Each perl script runs in its own Unix process, so one perl script can't interfere with another. Command line options can also be used to
deal with programs that have memory leaks or other problems that might keep them from otherwise running persistently.
The speedy front end connects to the back end process, speedy_backend, via a Unix socket in /tmp. A queue is kept in a shared file in /tmp
that holds an entry for each process. In that queue are the pids of the perl processes waiting for connections. The frontend pulls a
process out of this queue, connects to its socket, sends over the environment and argv, and then uses this socket for stdin/stdout to the
perl process.
FILES
/tmp/speedy* A unix socket used to connect to the frontend process.
AUTHOR
Sam Horrocks
http://daemoninc.com
sam@daemoninc.com
NOTES
This manual page was created by Niko Tyni <ntyni@iki.fi> for Debian GNU/Linux, because the original program does not have one. It is based
on the original and more complete CGI::SpeedyCGI(3pm) manual page.
SEE ALSO
perl(1), CGI::SpeedyCGI(3pm), speedy(1)
SPEEDY_BACKEND(1p)