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Full Discussion: grep sed and a loop
Top Forums UNIX for Dummies Questions & Answers grep sed and a loop Post 302521302 by gunnahafta on Tuesday 10th of May 2011 09:47:04 PM
Old 05-10-2011
grep sed and a loop
Smilie

I have a requirement to search a log file that never rotates for certain values. If I find them I pipe them to a another file. To log file is constanyl being appened with new lines and never rotating Easy so far.

The problem is I dont want to pipe out matches already seen before. One thing I tried was to use sed to put a # at the beginning of each line as it is read. Then the grep would ignore lines starting with #

My problem is I can get it to just add # to the unread lines, it adds another to all lines so each time the log is read so the earliest entries have loads of * infront of them.

I was tryin gto get it to ignore liens with # and then to a for loop for any the new lines e.g. for any not starting with # search for the string and add # to the front. This way is would only add # to lines that dont have one.
Here i swhat I was working with but just cant get that loop to work on lines not starting with #

Any help would be a awesome.

grep -v '^#' test.log | grep "Can not load CRL" This line ignores lines starting with # and greps the rest for "Can not load CRL"

sed 's/^/#/g' test.log > testnew.log The line adds the # to the front and creates output file testnew.log I want it to only add # to lines without a # already

mv testnew.log test.log This line renames\overwrites testnew.log and to test.log If anyone knows how i can write directly to the original file instead of having to write a new file and then overwrite the original would be great as well
 

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LEARN ABOUT MOJAVE

uulog

uulog(1)						      General Commands Manual							  uulog(1)

NAME

       uulog - display entries in the UUCP log file.

SYNOPSIS

       uulog  [-#]  [-n  lines] [-sf system] [-u user] [-DSF] [--lines lines] [--system system] [--user user] [--debuglog] [--statslog] [--follow]
       [--follow=system]

DESCRIPTION

       The uulog program can be used to display entries in the UUCP log file.  It can select the entries for a particular system or  a	particular
       user.  You can use it to see what has happened to your queued jobs in the past.	Different options may be used to select which parts of the
       file to display.

OPTIONS

       -#, -n lines, --lines lines
	    Here '#' is a number; e.g., `-10'.	The specified number of lines is displayed from the end of the log file.  The default is  to  dis-
	    play the entire log file, unless the -f, -F, or --follow options are used, in which case the default is to display 10 lines.

       -s system, --system system
	    Display only log entries pertaining to the specified system.

       -u, --user user
	    Display only log entries pertaining to the specified user.

       -D --debuglog
	    Display the debugging log file.

       -S, --statslog
	    Display the statistics log file.

       -F, --follow
	    Keep displaying the log file forever, printing new lines as they are appended to the log file.

       -f system, --follow=system
	    Keep displaying the log file forever, displaying only log entries pertaining to the specified system.

       Standard UUCP options:

       -X type, --debug type
	    Turn  on  particular debugging types.  The following types are recognized: abnormal, chat, handshake, uucp-proto, proto, port, config,
	    spooldir, execute, incoming, outgoing.  --debug option may appear multiple times.  A number may also be given, which will turn on that
	    many types from the foregoing list; for example, --debug 2 is equivalent to --debug abnormal,chat.

       -I file, --config
	    Set configuration file to use.

       -v, --version
	    Report version information and exit.

       --help
	    Print a help message and exit.

SEE ALSO

       uucp(1)

AUTHOR

       Ian Lance Taylor <ian@airs.com>.  Text for this Manpage comes from Taylor UUCP, version 1.07 Info documentation.

								 Taylor UUCP 1.07							  uulog(1)
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