Script to subtract rows HELP Post: 302520648

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Subtract date & time in diferent rows

Hi Friends :) I have a long file having fields in the form : Field1 yy/mm/dd hh:mm:ss Duration(Sec) line 1) 123123 05/11/30 12:12:56 145 line 2) 145235 05/11/30 12:15:15 30 line 3) 145264 05/11/30 13:14:56 178 . . I want to subtract yy/dd/dd hh:mm:ss in line (2) from yy/mm/dd hh:mm:ss in...

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Hello all, I have written sth like this: #!/bin/bash grep -e XXX -e YYYY myfile.log | grep -v ZZZ | awk '{print $1 " " $2 ";" $3 ";" $9 ";" $11}' > myfile.csv sed -i '1iDate;Time;From;To' myfile.csv => it is clear that it converts log to csv and add a header. Now I want to subtract row...

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LEARN ABOUT V7

calendar

CALENDAR(1)						      General Commands Manual						       CALENDAR(1)

NAME

       calendar - reminder service

SYNOPSIS

       calendar [ - ]

DESCRIPTION

       Calendar consults the file `calendar' in the current directory and prints out lines that contain today's or tomorrow's date anywhere in the
       line.  Most reasonable month-day dates such as `Dec. 7,' `december 7,' `12/7,' etc., are recognized, but not `7 December'  or  `7/12'.	On
       weekends `tomorrow' extends through Monday.

       When  an argument is present, calendar does its job for every user who has a file `calendar' in his login directory and sends him any posi-
       tive results by mail(1).  Normally this is done daily in the wee hours under control of cron(8).

FILES

       calendar
       /usr/lib/calendar to figure out today's and tomorrow's dates
       /etc/passwd
       /tmp/cal*
       egrep, sed, mail subprocesses

SEE ALSO

       at(1), cron(8), mail(1)

BUGS

       Your calendar must be public information for you to get reminder service.
       Calendar's extended idea of `tomorrow' doesn't account for holidays.

																       CALENDAR(1)

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Discussion started by: yairon

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script for add and subtract two hours

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