I need to append a number, for example 700, to the end of each record when the fourth field is >700 so I run the command as below which gives me the output that I wanted.
All good so far. Just want to know if there is a "better" way of writing this AWK construct?
Next thing is I wanted to add a column heading and get a clean printed output in tabular format sort of so I did as below:
Okay, so far so good. The only thing that I want to know now is whether there is an AWK function that will let me print x-number of dashes? Just so in matches the %-20s that am using in the printf?
I know it's a "cosmetic" thingy, I can easily just type in 20 dashes when am doing the echo. Just thought maybe there is an AWK function that will let me do it the "smart" way or any UNIX command that will let me do the same.
Any tips/suggestions will be much appreciated. Thanks in advance.
Let's say I write a simple script that contains the following:
date | awk '{print $1}'
date | awk '{print $2}'
Of course, when I run the script the output will look similar to:
Tue
Mar
What if I want my ouput to be on one line as follows:
Tue Mar
What changes would I need to... (2 Replies)
Hi All,
I'm having a problem with the way awk is interperting a space between double quotes in a for loop. Below is the code and output from running the script:
AWK for loop:
for i in $(awk 'BEGIN{FS=","}{print "Probe Name:" $1};{print "Probe Temp:" $2};{
print... (2 Replies)
Hi,
Ive used unix.com to help learn the basics of AWK to format txt files however ive run out of talent and could do with some help. Im not sure if this is possible using awk but I have an input as follows
L73-10 342 0 1480
L73-10 342 100 1480
L73-10 342 250 1656
L73-10 342 500 1746... (13 Replies)
Hi I have a file as given below:
<table border=1>
<TR><TH>Script Name</TH><TH>CVS Status</TH><TH>Script Location</TH></TR>
<TR><TD><CENTER>Work Area: /home/ustst/</CENTER></TD></TR>
<TR><TD><CENTER>admin_export.sh</CENTER></TD><TD><CENTER>Locally... (1 Reply)
Dear all
I require help with AWK regarding this situation
Input is :
fn1 12345
fn1 23456
fn3 231513
fn1 22325
fn3 123125
Desired output is
fn1 12345 23456 22325
fn3 231513 123125 (5 Replies)
when i try this awk its giving out put as below.
awk '!(/^$/||/--/||/selected/||/^ *$/){print $1}' tmp.txt
output
=====
1
2010-08-03-12.31.26.126000
how excluede the 1st line ? i mean i want output only 2nd line i.e 2010-08-03-12.31.26.126000; (5 Replies)
Hi all,
I'm writing a simple awk code:
awk 'BEGIN {FS="|"};{print "Type\tNumber\ttypes\tTotal";};{print $1, "\t", $2, "\t", $3, "\t", $4, "\t";}' db_query.txt
it gives me the result:
Type Number types Total
XXX 498.0 5100.0 5274.661
Type Number types Total... (7 Replies)
Hi,
I have a file below that I am wanting to awk. The lines of relevance are lines 7 and 9
$ nl /tmp/x
1 ADRCI: Release 11.2.0.3.0 - Production on Sun Jun 23 17:01:02 2013
2 Copyright (c) 1982, 2011, Oracle and/or its affiliates. All rights reserved.
3 ADR base =... (2 Replies)
Need assistance on the data extraction using awk
Below is the format and would like to extract the data in another format
-------------------------------------------------------------------------------------------------
Minimum Temperature (deg F )
DAY 1 2 3 4 5 6 7 8 9 10 11... (4 Replies)
i would like to format the 9 character with suffix as "0".
i tried below it doesn't work.
>a=12345
> echo $a | awk '{printf "%-09s\n",$1}'
>12345
required output is 123450000
can you guys help me out ? (7 Replies)
Discussion started by: expert
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)