I'm reading 2 input files but not getting expected value.
I should get an alpha value on file_1_data but not getting any.
Please help.
>cat test6.sh
awk '
FILENAME==ARGV { file_1_data=$0; print "----- 1 Line " NR " -----" $1; next }
FILENAME==ARGV { file_2_data=$0; print "----- 2... (1 Reply)
Hi people. I am new to shell scripting, so I need a little help. I want to create a script named that takes an argument as a file, Read the input file and look for occurrences of the current username (say abc.xyz) who is executing the script. On finding an occurrence of the username take that line... (2 Replies)
I am trying to read input for a C program (that expects input from the user) from a file using the shell command:
progname < filename
but it seems that the program considers the char '<'
as the first input, hence causing an "error" in my program.
I checked it with another program and it... (2 Replies)
Hi guys,
I am new to AWK and unix scripting. Please see below my problem and let me know if anyone you can help.
I have 2 input files (example given below)
Input file 2 is a standard file (it will not change) and we have to get the name (second column after comma) from it and append it... (5 Replies)
Hello,
Could somebody please give me an awk example on how to read from the standard input.
It means as the "read" function in Korn shell.
Thx in advance ... (3 Replies)
Can I do something like,
if($0==/^int.*$/) {
print "Declaration"
}
for an input like: int a=5;
If the syntax is right, it is not working for me, but I am not sure about the syntax. Please help.
Thanks,
Prasanna (1 Reply)
Hi,
I need to read the date from the input file. The format of the input file is as follows:
a_b_c_yyyymmdd.txt
I need to read the date(yyyymmdd) part from the name of the input file.
Would really appreciate if someone can help me in this regard
Thanks a lot. (1 Reply)
I am not able to capture the user input in this script(bash).There is prompt for user input.Could some one help me capture user input while reading afile?
while read line
do
echo "$i"
path1=$line
path2=`echo $line|sed s/new_dir/old_dir/`
echo "Do you want to replace?";... (4 Replies)
I have a process that requires me to read data from huge log files and find the most recent entry on a per-user basis. The number of users may fluctuate wildly month to month, so I can't code for it with names or a set number of variables to capture the data, and the files are large so I don't... (7 Replies)
Discussion started by: rbatte1
7 Replies
LEARN ABOUT OSX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD