I like that just a little better, because I get less whitespace in front of the output. Although, (at least for me, it is harder to understand the syntax)
Could you explain?
I would like to keep the ability to modify the number of columns removed from 6, to anything I need.
hi friends!
i have a script where a execute a veritas command, available_media wich retrieves me a list of tapes .lst
then i execute
cat /tmp/listtapes.lst | grep -v VL |sed '/^$/d'|awk -F, '{print $1, $3, $4, $9}
' > /tmp/media1.lst
but it prints all the columns instead of the four... (3 Replies)
Hi,
i have a file with content
00:01:20.613 'integer32' 459254
00:01:34.158 459556
00:01:36.626 'integer32' 459255
and i want to print only output as below
00:01:20.613 459254
00:01:34.158 459556
00:01:36.626 459255
i dont want the word 'integer32' which is the second column.
i... (2 Replies)
HI ,
I want to remove 5th and 6th column from a .csv file using awk.is there any way of this apart from writing the each field as below
awk -F, '{print $1,$2,$3,$7......$100}' OFS=, infile.
Thx,
Deepti (4 Replies)
HI ,
I have a comma delimiter file, in which I want to remove 8th and 9th column.
I tried removing those columns using the below code
awk 'BEGIN { FS=","; OFS="," } {$8=$9="";gsub(",+",",",$0)}1' infile
But the problem is 8th and 9th columns are user entered fields, theyvhave carriage... (1 Reply)
Is it possible to print the records that has only 1 value in 2nd column.
Ex:
input
awex1 1
awex1 2
awex1 3
assww 1
ader34 1
ader34 2
output
assww 1 (5 Replies)
Hi guys,
I have hundreds file like this, here I only show two of them:
file 1
feco4_s_BB95.log ZE_1=-1717.5206260
feco4_t_BB95.log ZE_1=-1717.5169250
feco5_s_BB95.log ZE_1=-1830.9322060... (11 Replies)
Hi all,
I want to set 10 set of strings into a variable where:
removing all spaces within each string
change the delimiter from "|" to ","
Currently, I've the below script like this:Table=`ten character strings with spaces in-between and each string with delimiter "|" | tr -d ' ' |... (7 Replies)
I am working on a file with several columns as below
MO_NAME,FAULT_TYPE,CLASS,CODE1,CODE2,CODE3
RXOCF-101,BTS INTERNAL,FAULT CODES CLASS 2A,53,58
RXOCF-101,BTS INTERNAL,FAULT CODES CLASS 2B,24
RXOCF-101,BTS INTERNAL,FAULT CODES CLASS 2A,33
RXOCF-101,BTS INTERNAL,FAULT CODES CLASS 2D,57 ... (12 Replies)
Hi,
Can anyone help with the below please?
I have written some code which takes an input file, and and prints the contents out to a new file - it then loops round and prints the same columns, but increments the ID column by 1 each time.
Input file;
NAME,1,15-Dec-15,
NAME,1,21-Dec-15,... (9 Replies)
Hi,
I'm trying to copy and paste the sixth column from a bunch of files into a single file having each column pasted in separate columns (and not one after each other in just one column.)
I tried this code but works only partially because it copied and pasted 50 rows of each column... (6 Replies)
Discussion started by: Frastra
6 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)