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Top Forums Shell Programming and Scripting Finding longest line in a Record Post 302515078 by matrixmadhan on Tuesday 19th of April 2011 02:10:45 AM
Old 04-19-2011
Quote:
Originally Posted by pravin27
Could this help you?
Code:
len=3
awk -v l=$len 'length($1)>l { l=length($1);rec=$0} END {print l," ", rec}' inputfile

Its not $1, its $0 - small change to what you have posted

Code:
awk -v l=0 'length($0)>l { l=length($0);rec=$0} END {print l," ", rec}' inputfile

This User Gave Thanks to matrixmadhan For This Post:
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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