Sponsored Content
Top Forums Shell Programming and Scripting Extracting Directory From Path Post 302514481 by kurumi on Friday 15th of April 2011 09:42:09 PM
Old 04-15-2011
Code:
$ echo "/home/one/two/three/" | ruby -e 'puts gets.gsub(/\/$/,"").split("/")[-1]'
three

$ echo "/home/one/two/three/" | ruby -e 'puts gets.split("/")[-2]'
three

This User Gave Thanks to kurumi For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

extracting a field from directory path ??????

Hi I'll be getting a directory path as the input to the script. E.g. 1 abc/fsg/sdfhgsa/fasgfsd/adfghad/XXX/fhsad e.g. 2 sadfg/sadgjhgds/sd/dtuc/cghcx/dtyue/dfghsdd/XXX/qytq This input will be stored in a variable. My query is how to extract the field in a variable VAR which occurs... (15 Replies)
Discussion started by: skyineyes
15 Replies

2. Shell Programming and Scripting

Extracting file name from path

if I have a variable value "filetoprocess" equal to "/aaa/bbb/ccc" How can I simply extract the file name of "ccc" (4 Replies)
Discussion started by: ytakbob
4 Replies

3. UNIX for Dummies Questions & Answers

Extracting parts from an absolute path

Hi, How can I extract parts from an absolute path? For example : The absolute path is /dir1/dir2/dir3/dir4/dir5.I need the relative path starting with directory given as parameter : for instance if the parameter is dir3 then the result should be dir3/dir4/dir5 I need generic solution... (9 Replies)
Discussion started by: mortanon
9 Replies

4. Shell Programming and Scripting

Retrieve directory path from full file path through sh

Hi, I have a file abcd.txt which has contents in the form of full path file names i.e. $home> vi abcd.txt /a/b/c/r1.txt /q/w/e/r2.txt /z/x/c/r3.txt Now I want to retrieve only the directory path name for each row i.e /a/b/c/ /q/w/e/ How to get the same through shell script?... (7 Replies)
Discussion started by: royzlife
7 Replies

5. Shell Programming and Scripting

sed/awk for extracting directory from file path

Hi, I have following path: set file_path = D:/forums/prac/somedir/new1/file1.txt or set file_path = E:/new/forums1/prac/somedir/new2/file2.txt I need to grep "somedir" from file path. In this case preceding directory "prac" remains same for both the paths, but directories preceding... (7 Replies)
Discussion started by: sarbjit
7 Replies

6. Shell Programming and Scripting

"find . -printf" without prepended "." path? Getting path to current working directory?

If I enter (simplified): find . -printf "%p\n" then all files in the output are prepended by a "." like ./local/share/test23.log How can achieve that a.) the leading "./" is omitted and/or b.) the full path to the current directory is inserted (enclosed by brackets and a blank)... (1 Reply)
Discussion started by: pstein
1 Replies

7. UNIX for Dummies Questions & Answers

Extract directory name from the full directory path in UNIX using shell scripting

My input is as below : /splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt /splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt /splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt /splunk/scrubbed/triumph/ifind.triumph.txt From the above input I want to extract the file names only . Basically I want to... (5 Replies)
Discussion started by: IshuGupta
5 Replies

8. UNIX for Beginners Questions & Answers

Extracting directory portion.

Dear Experts, I have some directory structure something like follows. I would like to cut portion of it. Would you please help me? I have to run this on several sql's. The directory path is dynamic. I have cut what comes after first "sql" string. Input:... (3 Replies)
Discussion started by: srikanth38
3 Replies

9. UNIX for Beginners Questions & Answers

Convert Relative path to Absolute path, without changing directory to the file location.

Hello, I am creating a file with all the source folders included in my git branch, when i grep for the used source, i found source included as relative path instead of absolute path, how can convert relative path to absolute path without changing directory to that folder and using readlink -f ? ... (4 Replies)
Discussion started by: Sekhar419
4 Replies

10. UNIX for Beginners Questions & Answers

What is the difference ../directory path and ./directory path in ksh?

What is the difference ../directory path and ./directory path in ksh? (1 Reply)
Discussion started by: TestKing
1 Replies
Path::Dispatcher::Cookbook(3pm) 			User Contributed Perl Documentation			   Path::Dispatcher::Cookbook(3pm)

NAME
Path::Dispatcher::Cookbook - A cookbook for Path::Dispatcher RECIPES
How can I change the path delimiter from a space ' ' to a slash '/'? When importing the Path::Dispatcher::Declarative sugar, specify the "token_delimiter" option for the "default" group. package My::Dispatcher; use Path::Dispatcher::Declarative -base, -default => { token_delimiter => '/', }; Or define a subclass of Path::Dispatcher::Declarative with a "token_delimiter" method: package Web::Dispatcher::Maker; use base 'Path::Dispatcher::Declarative'; use constant token_delimiter => '/'; package My::Dispatcher; use Web::Dispatcher::Maker -base; How can I do rule chaining (like in Catalyst)? You can use a "chain" rule approximate chaining behavior: package MyDispatcher; use Path::Dispatcher::Declarative -base; under show => sub { chain { print "Displaying "; }; on inventory => sub { print "inventory: "; ... }; on score => sub { print "score: "; ... }; }; package main; MyDispatcher->run("show inventory"); # "Displaying inventory: ..." MyDispatcher->run("show score"); # "Displaying score: ..." How can I configure tab completion for shells? First add a dispatcher rule for generating completions based on the path. Here we name it _gencomp, so that if the user types "app _gencomp hel" it will print out the various completions of "hel". on qr/^_gencomps*(.*)/ => sub { my $prefix = shift->pos(1); $prefix = "" if !defined($prefix); print "$_ " for dispatcher->complete($prefix); }; Then tell your shell about how to use _gencomp. For zsh it might look like this (replace "APP" with your binary name): /usr/share/zsh/site-functions/_APP: #compdef APP typeset -a APP_completions APP_completions=($($words[1] _gencomp $words[2,-1])) compadd $APP_completions For bash it might look like this: /etc/bash_completion.d/APP.bash: function _APP_() { COMPREPLY=($($1 _gencomp ${COMP_WORDS[COMP_CWORD]})) } complete -F _APP_ APP perl v5.12.4 2011-08-30 Path::Dispatcher::Cookbook(3pm)
All times are GMT -4. The time now is 05:19 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy