Hi
I'll be getting a directory path as the input to the script.
E.g. 1 abc/fsg/sdfhgsa/fasgfsd/adfghad/XXX/fhsad
e.g. 2 sadfg/sadgjhgds/sd/dtuc/cghcx/dtyue/dfghsdd/XXX/qytq
This input will be stored in a variable.
My query is how to extract the field in a variable VAR which occurs... (15 Replies)
Hi,
How can I extract parts from an absolute path?
For example :
The absolute path is /dir1/dir2/dir3/dir4/dir5.I need the relative path starting with directory given as parameter : for instance if the parameter is dir3 then the result should be dir3/dir4/dir5
I need generic solution... (9 Replies)
Hi,
I have a file abcd.txt which has contents in the form of full path file names i.e.
$home> vi abcd.txt
/a/b/c/r1.txt
/q/w/e/r2.txt
/z/x/c/r3.txt
Now I want to retrieve only the directory path name for each row
i.e
/a/b/c/
/q/w/e/
How to get the same through shell script?... (7 Replies)
Hi,
I have following path:
set file_path = D:/forums/prac/somedir/new1/file1.txt
or set file_path = E:/new/forums1/prac/somedir/new2/file2.txt
I need to grep "somedir" from file path. In this case preceding directory "prac" remains same for both the paths, but directories preceding... (7 Replies)
If I enter (simplified):
find . -printf "%p\n"
then all files in the output are prepended by a "." like
./local/share/test23.log
How can achieve that
a.) the leading "./" is omitted
and/or
b.) the full path to the current directory is inserted (enclosed by brackets and a blank)... (1 Reply)
My input is as below :
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt
/splunk/scrubbed/triumph/ifind.triumph.txt
From the above input I want to extract the file names only .
Basically I want to... (5 Replies)
Dear Experts,
I have some directory structure something like follows. I would like to cut portion of it. Would you please help me? I have to run this on several sql's. The directory path is dynamic. I have cut what comes after first "sql" string.
Input:... (3 Replies)
Hello,
I am creating a file with all the source folders included in my git branch, when i grep for the used source, i found source included as relative path instead of absolute path, how can convert relative path to absolute path without changing directory to that folder and using readlink -f ? ... (4 Replies)
What is the difference ../directory path and ./directory path in ksh? (1 Reply)
Discussion started by: TestKing
1 Replies
LEARN ABOUT DEBIAN
path::dispatcher::cookbook
Path::Dispatcher::Cookbook(3pm) User Contributed Perl Documentation Path::Dispatcher::Cookbook(3pm)NAME
Path::Dispatcher::Cookbook - A cookbook for Path::Dispatcher
RECIPES
How can I change the path delimiter from a space ' ' to a slash '/'?
When importing the Path::Dispatcher::Declarative sugar, specify the "token_delimiter" option for the "default" group.
package My::Dispatcher;
use Path::Dispatcher::Declarative -base, -default => {
token_delimiter => '/',
};
Or define a subclass of Path::Dispatcher::Declarative with a "token_delimiter" method:
package Web::Dispatcher::Maker;
use base 'Path::Dispatcher::Declarative';
use constant token_delimiter => '/';
package My::Dispatcher;
use Web::Dispatcher::Maker -base;
How can I do rule chaining (like in Catalyst)?
You can use a "chain" rule approximate chaining behavior:
package MyDispatcher;
use Path::Dispatcher::Declarative -base;
under show => sub {
chain {
print "Displaying ";
};
on inventory => sub {
print "inventory:
";
...
};
on score => sub {
print "score:
";
...
};
};
package main;
MyDispatcher->run("show inventory"); # "Displaying inventory:
..."
MyDispatcher->run("show score"); # "Displaying score:
..."
How can I configure tab completion for shells?
First add a dispatcher rule for generating completions based on the path. Here we name it _gencomp, so that if the user types "app _gencomp
hel" it will print out the various completions of "hel".
on qr/^_gencomps*(.*)/ => sub {
my $prefix = shift->pos(1);
$prefix = "" if !defined($prefix);
print "$_
" for dispatcher->complete($prefix);
};
Then tell your shell about how to use _gencomp. For zsh it might look like this (replace "APP" with your binary name):
/usr/share/zsh/site-functions/_APP:
#compdef APP
typeset -a APP_completions
APP_completions=($($words[1] _gencomp $words[2,-1]))
compadd $APP_completions
For bash it might look like this:
/etc/bash_completion.d/APP.bash:
function _APP_()
{
COMPREPLY=($($1 _gencomp ${COMP_WORDS[COMP_CWORD]}))
}
complete -F _APP_ APP
perl v5.12.4 2011-08-30 Path::Dispatcher::Cookbook(3pm)