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sed/awk for extracting directory from file path

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# 1  
Old 08-12-2011
Error sed/awk for extracting directory from file path
Hi,

I have following path:

set file_path = D:/forums/prac/somedir/new1/file1.txt

or set file_path = E:/new/forums1/prac/somedir/new2/file2.txt

I need to grep "somedir" from file path. In this case preceding directory "prac" remains same for both the paths, but directories preceding "prac" or after "somedir" are variable.

I know sed code which can give only complete dir path as :

Code:
echo $somedir | sed 's#\(.*\)/.*#\1#'

Thanks in Advance
# 2  
Old 08-12-2011
If you don't mind, please post the sample output you desire. Would help us understand a little better.
# 3  
Old 08-12-2011
Quote:
Originally Posted by dude2cool
If you don't mind, please post the sample output you desire. Would help us understand a little better.
I want "somedir" as output from this file path keeping in mind that this file path is variable but somedir will always comes after "prac" directory.
# 4  
Old 08-12-2011
Here you go:

Code:
 echo "E:/new/forums1/prac/somedir/new2/file2.txt"|awk -F"/" '{split($0,a,"/")} {for(i=1;i<=NF;i++) { if (a[i] == "prac")print a[i+1]}}'

The above will output somedir.
# 5  
Old 08-12-2011
How about this:

Code:
$ cat infile
D:/forums/prac/somedir/new1/file1.txt
E:/new/forums1/prac/somedir/new2/file2.txt
X:/not/this/one/file3.txt
X:/unpractile/somedir/one/file4.txt
 
$ sed -n 's/.*\/prac\/.*somedir\/.*$/somedir/p' infile
somedir
somedir

# 6  
Old 08-12-2011
Or...
Code:
echo $somedir | awk '/prac/{getline;print}' RS=/

# 7  
Old 08-12-2011
Alternate sed..
Code:
echo 'E:/new/forums1/prac/somedir/new2/file2.txt'| sed 's|.*prac.\([^/]*\)/.*|\1|'

echo 'D:/forums/prac/somedir/new1/file1.txt'|      sed 's|.*prac.\([^/]*\)/.*|\1|'
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