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Top Forums Shell Programming and Scripting Problem with Variable and AWK command Post 302509088 by mkjp2011 on Tuesday 29th of March 2011 07:27:51 PM
Old 03-29-2011
Problem with Variable and AWK command

Okay, so I am trying to use a count variable to reference the column of output sent from an echo statement. So I am trying to do this

Code:
 
#!/bin/bash
CURRENT=$PWD 
VAR=3
CHANGE=`echo $CURRENT | awk -F "/" '{ print \$$VAR }'`

This instead of giving me the third instance after the "/" gives me the whole path. Why is this? How can I use the current method or is there a better way to parse the PWD String?
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +--------------------+-----------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +--------------------+-----------------+ |Availability | SUNWgawk | +--------------------+-----------------+ |Interface Stability | Volatile | +--------------------+-----------------+ NOTES
Source for gawk is available on http://opensolaris.org. Free Software Foundation Nov 3 1999 IGAWK(1)
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