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Top Forums Programming Need help with Card Dealing Program Post 302508619 by Corona688 on Monday 28th of March 2011 02:18:11 PM
Old 03-28-2011
Why not have each card as a unique number, and decide from that number what suit it is? The suit defines the color, so that solves both problems.

Code:
#include <stdio.h>

enum suit_t
{
        // Arranged in this order to get black/red/black/red.
        SUIT_CLUB=0,    // 0 & 1 == 0.  Black.
        SUIT_HEART=1,   // 1 & 1 == 1.  Red.
        SUIT_SPADE=2,   // 2 & 1 == 0.  Black.
        SUIT_DIAMOND=3  // 3 & 1 == 1.  Red.
};

enum card_t
{
        CARD_MIN=0, CARD_MAX=52,

        // Cards are numbered as 0, 4, 8, 12, etc.  The first 2 bits decide the suit.
        CARD_ACE=(0<<2),      CARD_2=(1<<2),
        CARD_3=(2<<2),          CARD_4=(3<<2),
        CARD_5=(4<<2),          CARD_6=(5<<2),
        CARD_7=(6<<2),          CARD_8=(7<<2),
        CARD_9=(8<<2),          CARD_10=(9<<2),
        CARD_JACK=(10<<2),      CARD_QUEEN=(11<<2),
        CARD_KING=(12<<2)
};

const char const *cardnames[]={
        "Ace", "Two", "Three", "Four", "Five", "Six", "Seven",
        "Eight", "Nine", "Ten", "Jack", "Queen", "King", NULL };

const char const *colornames[]={ "Black", "Red", NULL };
const char const *suitnames[]={"Clubs", "Hearts", "Spades", "Diamonds", NULL };

#define CARD_NAMESTR(X)         (cardnames[(X)>>2])
#define CARD_SUITSTR(X)         (suitnames[(X)&SUIT_DIAMOND])
#define CARD_COLORSTR(X)        (colornames[((X)&1)])

int main(void)
{
        int card;

        for(card=CARD_MIN; card < CARD_MAX; card++)
        {
                printf("card %d is the %s of %s, and is %s\n", card,
                        CARD_NAMESTR(card), CARD_SUITSTR(card),
                        CARD_COLORSTR(card));
        }
}

Code:
card 0 is the Ace of Clubs, and is Black
card 1 is the Ace of Hearts, and is Red
card 2 is the Ace of Spades, and is Black
card 3 is the Ace of Diamonds, and is Red
card 4 is the Two of Clubs, and is Black
card 5 is the Two of Hearts, and is Red
card 6 is the Two of Spades, and is Black
card 7 is the Two of Diamonds, and is Red
...
card 44 is the Queen of Clubs, and is Black
card 45 is the Queen of Hearts, and is Red
card 46 is the Queen of Spades, and is Black
card 47 is the Queen of Diamonds, and is Red
card 48 is the King of Clubs, and is Black
card 49 is the King of Hearts, and is Red
card 50 is the King of Spades, and is Black
card 51 is the King of Diamonds, and is Red


Last edited by Corona688; 03-28-2011 at 03:36 PM..
 

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ppmdither(1)						      General Commands Manual						      ppmdither(1)

NAME
ppmdither - ordered dither for color images SYNOPSIS
ppmdither [-dim power] [-red shades] [-green shades] [-blue shades] [ppmfile] DESCRIPTION
Reads a portable pixmap as input, and applies dithering to it to reduce the number of colors used down to the specified number of shades for each primary. The default number of shades is red=5, green=9, blue=5, for a total of 225 colors. To convert the image to a binary rgb format suitable for color printers, use -red 2 -green 2 -blue 2. OPTIONS
-dim power The size of the dithering matrix. The dithering matrix is a square whose dimension is a power of 2. power is that power of 2. The default is 4, for a 16 by 16 matrix. -red shades The number of red shades to be used, including black; minimum of 2. -green shades The number of green shades to be used, including black; minimum of 2. -blue shades The number of blue shades to be used, including black; minimum of 2. SEE ALSO
pnmdepth(1), ppmquant(1), ppm(5) AUTHOR
Copyright (C) 1991 by Christos Zoulas. 14 July 1991 ppmdither(1)
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