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Top Forums Programming Need help with Card Dealing Program Post 302508619 by Corona688 on Monday 28th of March 2011 02:18:11 PM
Old 03-28-2011
Why not have each card as a unique number, and decide from that number what suit it is? The suit defines the color, so that solves both problems.

Code:
#include <stdio.h>

enum suit_t
{
        // Arranged in this order to get black/red/black/red.
        SUIT_CLUB=0,    // 0 & 1 == 0.  Black.
        SUIT_HEART=1,   // 1 & 1 == 1.  Red.
        SUIT_SPADE=2,   // 2 & 1 == 0.  Black.
        SUIT_DIAMOND=3  // 3 & 1 == 1.  Red.
};

enum card_t
{
        CARD_MIN=0, CARD_MAX=52,

        // Cards are numbered as 0, 4, 8, 12, etc.  The first 2 bits decide the suit.
        CARD_ACE=(0<<2),      CARD_2=(1<<2),
        CARD_3=(2<<2),          CARD_4=(3<<2),
        CARD_5=(4<<2),          CARD_6=(5<<2),
        CARD_7=(6<<2),          CARD_8=(7<<2),
        CARD_9=(8<<2),          CARD_10=(9<<2),
        CARD_JACK=(10<<2),      CARD_QUEEN=(11<<2),
        CARD_KING=(12<<2)
};

const char const *cardnames[]={
        "Ace", "Two", "Three", "Four", "Five", "Six", "Seven",
        "Eight", "Nine", "Ten", "Jack", "Queen", "King", NULL };

const char const *colornames[]={ "Black", "Red", NULL };
const char const *suitnames[]={"Clubs", "Hearts", "Spades", "Diamonds", NULL };

#define CARD_NAMESTR(X)         (cardnames[(X)>>2])
#define CARD_SUITSTR(X)         (suitnames[(X)&SUIT_DIAMOND])
#define CARD_COLORSTR(X)        (colornames[((X)&1)])

int main(void)
{
        int card;

        for(card=CARD_MIN; card < CARD_MAX; card++)
        {
                printf("card %d is the %s of %s, and is %s\n", card,
                        CARD_NAMESTR(card), CARD_SUITSTR(card),
                        CARD_COLORSTR(card));
        }
}

Code:
card 0 is the Ace of Clubs, and is Black
card 1 is the Ace of Hearts, and is Red
card 2 is the Ace of Spades, and is Black
card 3 is the Ace of Diamonds, and is Red
card 4 is the Two of Clubs, and is Black
card 5 is the Two of Hearts, and is Red
card 6 is the Two of Spades, and is Black
card 7 is the Two of Diamonds, and is Red
...
card 44 is the Queen of Clubs, and is Black
card 45 is the Queen of Hearts, and is Red
card 46 is the Queen of Spades, and is Black
card 47 is the Queen of Diamonds, and is Red
card 48 is the King of Clubs, and is Black
card 49 is the King of Hearts, and is Red
card 50 is the King of Spades, and is Black
card 51 is the King of Diamonds, and is Red


Last edited by Corona688; 03-28-2011 at 03:36 PM..
 

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Ace::Graphics::Glyph::triangle(3pm)			User Contributed Perl Documentation		       Ace::Graphics::Glyph::triangle(3pm)

NAME
Ace::Graphics::Glyph::ex - The "triangle" glyph SYNOPSIS
See L<Ace::Graphics::Panel> and L<Ace::Graphics::Glyph>. DESCRIPTION
This glyph draws an isoceles triangle. It is possible to draw the triangle with the base on the N, S, E, or W side. OPTIONS In addition to the common options, the following glyph-specific options are recognized: Option Description Default ------ ----------- ------- -point Whether to draw a triangle feature width with base the scaled width of the feature or length point. -orient On which side shall the S base be? (NSEW) BUGS
Please report them. SEE ALSO
Ace::Sequence, Ace::Sequence::Feature, Ace::Graphics::Panel, Ace::Graphics::Track, Ace::Graphics::Glyph::anchored_arrow, Ace::Graphics::Glyph::arrow, Ace::Graphics::Glyph::box, Ace::Graphics::Glyph::primers, Ace::Graphics::Glyph::segments, Ace::Graphics::Glyph::toomany, Ace::Graphics::Glyph::transcript, AUTHOR
Allen Day <day@cshl.org>. Copyright (c) 2001 Cold Spring Harbor Laboratory This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself. See DISCLAIMER.txt for disclaimers of warranty. perl v5.14.2 2001-05-15 Ace::Graphics::Glyph::triangle(3pm)
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