awk question. Post: 302505761

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awk question

I have the following error: ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }' Syntax Error The source line is 1. The error context is BEGIN >>> NR <<< > 1 { print $2, $9 } awk: 0602-500 Quitting The source line is 1. What I want to do is ls a directory, skip the first...

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Hello, I have the following command that does 2 searches. awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE How do I search up after the first search? thanks

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i have a little awk script that I use looks this: awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled. i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled....

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I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text. Can anyone provide some assistance. Thanks!!

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How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06 4.35109e+06 4.36134e+06 4.4535e+06 5.47752e+06 5.48777e+06 7.52554e+06 7.73036e+06 9.06158e+06 :confused: thank you

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Hi, in the following script, what does " a=$0} END " mean ? do we need that ? Thanks awk '{a=$0} END {for (i=NR; i>=1; i--) print a}' file

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Can anyone help with this this one liner: nawk -v RS='' '$1=$1' InputFile What I have in the file: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958 -0.0005763523138347 0.0 And the output I want: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958...

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Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello...

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Hi Experts, I am trying to get system output to capture inside awk , but not working: Please advise if this is possible : I am trying something like this but not working, the output is coming wrong: echo "" | awk '{d=system ("date") ; print "Current date is:" , d }' Thanks,

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Please help me with this ... Input file N_DC_Fabric_A,AU_SAP01,c050760169900000(*),50060169472007fc(*),50060160472007fc(*), N_DC_Fabric_A,AU_SAP02,c050760169900004,50060169472007fc(*),50060160472007fc(*), N_DC_Fabric_A,AU_SAP03,c050760169900004,50060169472007fc,50060160472007fc, ...

LEARN ABOUT NETBSD

zegrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD

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LEARN ABOUT NETBSD

zegrep