Hi,
I'm trying to write a shell script that has a menu and then dependant on the selection, will automate some samba file transfer.
The problem is when I run the code without the case statement it runs fine. but when I put the case statement in the only way I can get the code to run is to... (6 Replies)
Hi I am trying to create a shell script that will
look for a contracthead file first and if the contract head file does not exist on day1 exit script.
Now on day2 if contracthead exists or not run the script uploading files in order
such as contract line then contract contact
so the... (2 Replies)
In a case statement like below :
case $rental in
"car") echo "For $rental Rs.20 per k/m";;
"van") echo "For $rental Rs.10 per k/m";;
"jeep") echo "For $rental Rs.5 per k/m";;
"bicycle") echo "For $rental 20 paisa per k/m";;
*) echo "Sorry, I can not gat a $rental for you";;... (4 Replies)
Hi there
I have a database on a remote box and i have been using shell script to insert data into it for example, i could have a script that did this
SN=123456
n=server1
m=x4140
sql="UPDATE main SET hostname='$n',model='$m' WHERE serial='$SN';"
echo $sql |/usr/sfw/bin/mysql -h... (4 Replies)
Hello I am very new to shell and I bought some books and trying to learn it. I started trying to write a script that will take a number and count it down to 1 with commas in between. This number can only be one argument. If lower than one or higher than one argument it sends an error message. ... (4 Replies)
Hello forum members.
please go through the below mentioned issue and let me know the right solution.
I have to write a script which runs another script .the executable script take input parmeters.so iam writing the the script below .
Sample Code:Begins
#! /bin/ksh
echo " enter... (2 Replies)
I want to make the file test condition a variable ($Prmshn in code below).
My goal is to use something like the first three unsuccessful if statetments since the 'if
#!/bin/ksh
test_input()
{
Prmshn=${1}
InFLNm=${2}
ifReq="-$Prmshn $InFLNm"
#the following three if statments fail:
#if ] ;... (10 Replies)
Hi All, when I executed the query in normal unix mode, the output is
expected. if I executed the query using shell script, I am not getting the result. not sure whether I need to use dbms_output.put_line or echo.
dbms_output.put_line("COUNTRY_CODE"||" "||"SUB_TYPE"||" ... (3 Replies)
have written the below code to check whether the string received from user is a file name or dir using case statement, but its going into default case*).
#!/bin/sh
#Get a string from user and check whether its a existing filename or not
rm str2
rm str3
echo "enter a file \c"
read fil... (8 Replies)
Please see part of a shell script below.
#Move folder to HOT folder
echo " moving $PRE_OCR_DIR/$BATCHNAME to $HOT_FOLDER_DIR\n"
#chmod -R 777 $PRE_OCR_DIR/$BATCHNAME
mv $PRE_OCR_DIR/$BATCHNAME $HOT_FOLDER_DIR
I wish to write an if statement around the move
that if that if $BATCHNAME... (3 Replies)
Discussion started by: worky
3 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)