Sponsored Content
Full Discussion: Finding a pattern with grep
Top Forums UNIX for Dummies Questions & Answers Finding a pattern with grep Post 302503659 by royalibrahim on Friday 11th of March 2011 08:58:30 AM
Old 03-11-2011
Quote:
Originally Posted by vistastar
tested in bash:
Code:
grep -E '(.)\1(.)\2{1}\1(.)\3'

Wonderful !! but could you please explain us the logic. Its very hard to crack Smilie
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

finding duplicate files by size and finding pattern matching and its count

Hi, I have a challenging task,in which i have to find the duplicate files by its name and size,then i need to take anyone of the file.Then i need to open the file and find for more than one pattern and count of that pattern. Note:These are the samples of two files,but i can have more... (2 Replies)
Discussion started by: jerome Sukumar
2 Replies

2. Shell Programming and Scripting

Finding Last occurance of another pattern when a pattern is found.

Hi, I have two files viz, rak1: $ cat rak1 rak2: $ cat rak2 sdiff rak1 rak2 returns: I want the lines that got modified, changed, or deleted preceding with the section they are in. I have done this so far: (1 Reply)
Discussion started by: rakeshou
1 Replies

3. Shell Programming and Scripting

Want to grep for a pattern and display the content above that pattern

Hi, When we have a failure, sometimes we just step restart the job from the next step. Later when we open the log for analysis of the failure, it is becoming difficult to go to the failure part. For eg., if it is a 1000 line log, the failure may be at 500th line. so wat i want to do is, grep... (6 Replies)
Discussion started by: ajayakunuri
6 Replies

4. UNIX for Dummies Questions & Answers

Finding a pattern

Hi, I have the below content in file: <xmlfile> ows_Body="Hi" ows_Title="Title" ows_Author="krishna" </xmlfile> I wanted to remove ows_Body content from the file. I am using the below code sed -e 's/ows_Body.*ows/ows/g' Giving output: (9 Replies)
Discussion started by: mahish20
9 Replies

5. Homework & Coursework Questions

finding pattern without grep in unix

how can i find related pattern in a text file without using grep command in unix (2 Replies)
Discussion started by: feint
2 Replies

6. UNIX for Dummies Questions & Answers

Finding Pattern

Hi, i need some help regarding finding a pattern in files inside a direstory. i have these files abc123.txt cemj111.txt ckmem.txt cmick.txt crnnc.txt montt.txt xyz123.txt dfd123.txt cvv123.txt i need to find the files with name "*123.txt" which does not contain a perticular... (2 Replies)
Discussion started by: debu182
2 Replies

7. Shell Programming and Scripting

Finding the pattern and replacing the pattern inside the file

i have little challenge, help me out.i have a file where i have a value declared and and i have to replace the value when called. for example i have the value for abc and ccc. now i have to substitute the value of value abc and ccc in the place of them. Input File: go to &abc=ddd; if... (16 Replies)
Discussion started by: saaisiva
16 Replies

8. Shell Programming and Scripting

sed and awk usage to grep a pattern 1 and with reference to this grep a pattern 2 and pattern 3

Hi , I have a file where i have modifed certain things compared to original file . The difference of the original file and modified file is as follows. # diff mir_lex.c.modified mir_lex.c.orig 3209c3209 < if(yy_current_buffer -> yy_is_our_buffer == 0) { --- >... (5 Replies)
Discussion started by: breezevinay
5 Replies

9. UNIX for Dummies Questions & Answers

Grep -v lines starting with pattern 1 and not matching pattern 2

Hi all! Thanks for taking the time to view this! I want to grep out all lines of a file that starts with pattern 1 but also does not match with the second pattern. Example: Drink a soda Eat a banana Eat multiple bananas Drink an apple juice Eat an apple Eat multiple apples I... (8 Replies)
Discussion started by: demmel
8 Replies

10. Shell Programming and Scripting

[sed] Finding and sticking the pattern to the beginning of successive lines up to the next pattern

I have a file like below. 2018.07.01, Sunday 09:27 some text 123456789 0 21 0.06 0.07 0.00 2018.07.02, Monday 09:31 some text 123456789 1 41 0.26 0.32 0.00 09:39 some text 456789012 1 0.07 0.09 0.09 09:45 some text 932469494 1 55 0.29 0.36 0.00 16:49 some text 123456789 0 48 0.12 0.15 0.00... (9 Replies)
Discussion started by: father_7
9 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 06:59 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy