Sponsored Content
Homework and Emergencies Homework & Coursework Questions help with the date difference Post 302502689 by DGPickett on Tuesday 8th of March 2011 03:41:37 PM
Old 03-08-2011
One technique I have used is to start time on March 1 of a leap year, so the future stretches out as 4 year sets, some with an extra day at the very end. When subtracting from a 4 year set the months in rotation, one never needs 29, as the most variable month is at the residue at the end after you subtract 47 months.

In UNIX, one usually just goes to UNIX time, subtracts, and then goes forward evaluating the residue, but if the app needs time in months, then it is more a question of the carry on subtract of dates, and of course the months, the leap year.

So, how close is your program -- what is a defect case?
 

10 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

date difference

Hi...I need some help with a date script. I need to allow the user to enter the month (alpha) day (int) and year (YYYY) and count the difference in number of days since Jan 1, 1952 to the users date. I've been messing with this for about 10 hours and I think I'm just making the script worse =( ... (1 Reply)
Discussion started by: mtnbaby
1 Replies

2. UNIX for Dummies Questions & Answers

date difference

Hi Can any buddy give mi a simple program or logic or command which will get difference between two dates ex:diff between 20051008 2005908 is 24hours 12 min 2 sec regards (1 Reply)
Discussion started by: rajuMBT
1 Replies

3. Shell Programming and Scripting

date difference

if there are two date one is entered by user and another is system date than how can we finds day difference between these two date try to make it within 4 lines (2 Replies)
Discussion started by: piyush_movadiya
2 Replies

4. Linux

date difference

hi, i have 2 dates in the form: '20080315120030' and '20080310140030'. i.e. YYYYMMDDHHMMSS. i need a way of getting the difference between them using shell script. any thoughts? (14 Replies)
Discussion started by: muay_tb
14 Replies

5. Shell Programming and Scripting

difference in date

Hi All! I would like to know the time difference between two dates which are in same format... $ date -r abc Thu Oct 29 09:40:37 EDT 2009 $ date Fri Oct 30 02:07:03 EDT 2009 i would like to find the diff between these two dates in hours..please help..:) Regards, Kiran (3 Replies)
Discussion started by: dddkiran
3 Replies

6. Shell Programming and Scripting

Difference in date

Dear all, I fancy that I'm pretty competent in ksh, but I have someone on HP-UX wanting me to script up a simple interface to handle user alterations rather than giving them high privileges to run up SAM. This is all fairly straightforward, but I'm stuck on an epoch date issue. When we have... (6 Replies)
Discussion started by: rbatte1
6 Replies

7. Programming

Date difference

I tried the below code to find difference between two dates. It works fine if the day of the month is 2-digit number. But it fails when we have a single-digit day of month(ex:1-9). my code is as below. please help me soon. #!/usr/bin/perl -w use strict; use Time::Local; ... (2 Replies)
Discussion started by: anandrec
2 Replies

8. Shell Programming and Scripting

Date difference

HI All , i need a bash script to find the number of days between two dates . Format YYYY-MM-DD THanks, Neil (1 Reply)
Discussion started by: nevil
1 Replies

9. AIX

Time Difference between date and date -u

Hi Everyone, We are having an issue with date and date -u in our AIX Systems. We have checked environment variable TZ and /etc/environment and however, we could not rectify the difference. >date Thu Mar 19 22:31:40 IST 2015 >date -u Thu Mar 19 17:01:44 GMT 2015 Any clue... (5 Replies)
Discussion started by: madhav.kunapa
5 Replies

10. Shell Programming and Scripting

Difference between two date

Hi, I created a script for finding the duration of a job using the start and end time of the job. But the command doesnt calculate correct value if the duration is more than 24 hours. Any help would be really good . cat test1 --- start time 03/27/15 17:41:00 03/24/15 11:58:04 03/23/15... (3 Replies)
Discussion started by: rogerben
3 Replies
ARBITRON(8)						      System Manager's Manual						       ARBITRON(8)

 *

NAME
arbitron - arbitron mailboxes SYNOPSIS
arbitron [ -C config-file ] [ -o ] [ -u ] [ -l ] [ -p months ] [ -d days | -D mmddyyyy[:mmddyyyy] ] mailbox... DESCRIPTION
Arbitron collects and reports readership statistics for mailboxes on the server. It also optionally prunes the mailboxes of Seen state for dormant users. Arbitron produces one line of output per mailbox, reporting the mailbox name followed by a space, followed by the number of readers (and if -u is specified, followed by a colon and a comma-separated list of the readers userids), and if -o is not specified, another space and the number of subscribers (and if -u is specified, followed by a colon and a comma-separated list of the subscribers userids). IMPORTANT: This format is subject to change in future versions. Each "reader" is a distinct authentication identity which has "s" rights to the mailbox and which has SELECTed the mailbox within either the past days days or the specified date range. Users are not counted as reading their own personal mailboxes. Personal mailboxes are not reported unless there is at least one reader other than the mailboxes owner. Arbitron reads its configuration options out of the imapd.conf(5) file unless specified otherwise by -C. OPTIONS
-C config-file Read configuration options from config-file. -o "old way" -- do not report subscribers. -u Report userids in addition to the count(s). -l Enable long reporting (comma delimited table consisting of mbox, userid, r/s, start time, end time). -d days Count as a reader an authentication identity which has SELECTed the mailbox within days days. Default is 30. -D mmddyyyy[:mmddyyyy] Count as a reader an authentication identity which has SELECTed the mailbox within the given date range. The start date and optional end date are specified as 2-digit month of the year, 2-digit day of the month, and 4-digit year. If the end date is not specified, then the current system time is used as the end time. -p months Prune Seen state for users who have not SELECTed the mailbox within months months. Default is infinity. FILES
/etc/imapd.conf CMU
Project Cyrus ARBITRON(8)
All times are GMT -4. The time now is 07:47 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy