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Top Forums Shell Programming and Scripting ~~Unix command to count a particular word in the whole directory .~~ Post 302501899 by Rabbitsfoot on Saturday 5th of March 2011 02:07:13 PM
Old 03-05-2011
Question ~~Unix command to count a particular word in the whole directory .~~

Hi ,

i'm trying to count a particular word occurance in a whole directory..is this possible Smilie

say for example there is a directory with 100 files which and all the file may have the word 'aaa' in it ...how would i count the number of 'aaa' in those whole 100 files in a directory ?

thanks for your help
 

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pocount(1)						      Translate Toolkit 1.3.0							pocount(1)

NAME
pocount - Produces word counts and other statistics from a PO file. SYNOPSIS
pocount [--csv] [directory|file(s)] DESCRIPTION
pocount will count the number of strings and words in a PO file. If no files or directories argument are provided, pocount will recurse through all files from the current directory. Otherwise, it will recurse and count all files in the specified directory or in the specified PO files. OPTIONS
--csv changes the output format to CSV (Comma Seperated Values) for import into a spreadsheet. OUTPUT
In normal mode the following output is given: avmedia/source/viewer.po type strings words (source) words (translation) translated: 1 3 3 fuzzy: 0 0 n/a untranslated: 4 22 n/a Total: 5 25 3 review 1 3 n/a In CSV mode the following outut is shown: Filename, Translated Messages, Translated Source Words, Translated Target Words, Fuzzy Messages, Fuzzy Source Words, Untranslated Mes- sages, Untranslated Source Words, Review Messages, Review Source Words avmedia/source/viewer.po, 1, 3, 3, 0, 0, 4, 22, 1, 3 Totals are not provided in CSV mode. In normal mode a grand total and file count is provided if the number of files is greater than one. BUGS
There are some miscounts related to word breaks. Translate Toolkit 1.3.0 pocount(1)
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