Works on command line but not in script Post: 302501687

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Top Forums UNIX for Dummies Questions & Answers Works on command line but not in script Post 302501687 by anthonyjstewart on Friday 4th of March 2011 09:13:39 AM

03-04-2011

Registered User

EXAMPLE 1: COMMAND LINE STRING

Working command line command: grep -rl POP * | xargs sed -i 's/POP/MOM/g'

This command should access all files in the current directory that have POP in them. It should then replace all instances of POP with MOM.

There is no output except that the files that have the string POP in them have bene changed so they now have MOM in them.

EXAMPLE 2: SCRIPT BASED CHANGE

Below is the command line inside a script. The script runs, takes two parameters POP and MOM so you would run it like this:

Code:

bash findandreplace.sh POP MOM

./findandreplace.sh POP MOM

The contents of the script are below

Code:

#!/bin/bash
SHELL=/bin/bash
MAIL=/var/mail/root
PATH=/opt/local/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin

if [ -z "$1" ] || [ -z "$2" ]
then
  echo " "
  echo " "
  echo "Usage: findandreplace.sh string1 string2"
  echo " "
  echo "Example:  findandreplace.sh  begin  end"
  echo " "
  echo "This will find all instances of begin and replace with end"
  echo "within the current directory."
  echo " "
 exit -1
fi
grep -rl $1 * | xargs sed -i 's/$1/$2/g'

When I echo the command line above inside the script the command line is perfect. But it doesn't actually make the change.

Last edited by pludi; 03-04-2011 at 10:53 AM.. Reason: code tags please

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