sed command : print lines having no # at the begining
I am trying to print those line which has no # in the begining of the line.
The sed I used for this purpose as shown below is not giving the required output.
Code:
echo 'PDE 5600' | sed -n 's/^\!#/&/p'
Where lies the problem
Last edited by hiten.r.chauhan; 02-28-2011 at 04:02 AM..
Reason: error in typing
Is there a standard way to make a shell script read a file, or list, and skip each line that contains # at the begining, or ignores the content starting after a # in line?
I'm looking to mimic the way commenting in a shell script normally works. This way I can comment my text files and lists my... (4 Replies)
From the below file I want to grep only the lines except the comment sections. But grep -v "#" is eliminating the last line because it has one # in between.
Any idea how can I ignore only the lines which have # at the begining (I mean comment lines) ?
Thanks a lot to all in advance
C Saha (1 Reply)
Hello,
I'm trying to move the last word of matching pattern to the begining of next line. Appreciate if anyone post the script.
From the below line I'm getting the last word, Note: this word also appears in many places in my file
#return the last word of line that contains ListenPort
sed... (4 Replies)
Hello!
Im trying to read file contents. Then, print out every line that has "/bens/here" in the file that was read.
cat /my/file.now | sed '/bens/here/p'
I keep getting the error asking if I need to predeclare sed?
What does predeclaring sed mean?
Thanks!
Ben (2 Replies)
Hi guys.
I need a sed command to print like 10 lines after a regular expression is found in the log.
Can anyone help me out.
Thanks
---------- Post updated at 10:52 AM ---------- Previous update was at 10:34 AM ----------
never mind.
I just did the search bewteen two expressions. (1 Reply)
I am trying to extract a table of data (mysql query output) from a log file. I need to print everything below the header and not past the end of the table. I have spent many hours searching with little progress. I am matching the regexp +-\{99\} with no problem. I just can't figure out how to print... (5 Replies)
Hi All
I'm trying to extract the line just above a regexp and all lines after this.
I'm currently doing this in two steps
sed -n -e "/^+---/{g;p;}" -e h oldfile.txt > modified.txt
sed -e "1,/^+---/d" -e "/^$/d" oldfile.txt >>modified.txt
Sample
sometext will be here
sometext will be... (3 Replies)
I am getting the varible value from a grep command as:
var=$(grep "Group" File1.txt | sed 's/Group Name*//g;s/,//g;s/://g;s/-//g')
which leaves me the value of $var=xyz.
now i want to append $var value in the begining of all the lines present in the file. Can u please suggest?
Input file:
1... (10 Replies)
Use sed to print first n lines and last n lines of an output.
For example: n=10
Can it be done?
Thanks. (7 Replies)
Discussion started by: carloszhang
7 Replies
LEARN ABOUT LINUX
shtool-subst
SHTOOL-SUBST.TMP(1) GNU Portable Shell Tool SHTOOL-SUBST.TMP(1)NAME
shtool-subst - GNU shtool sed(1) substitution operations
SYNOPSIS
shtool subst [-v|--verbose] [-t|--trace] [-n|--nop] [-w|--warning] [-q|--quiet] [-s|--stealth] [-i|--interactive] [-b|--backup ext]
[-e|--exec cmd] [-f|--file cmd-file] [file] [file ...]
DESCRIPTION
This command applies one or more sed(1) substitution operations to stdin or any number of files.
OPTIONS
The following command line options are available.
-v, --verbose
Display some processing information.
-t, --trace
Enable the output of the essential shell commands which are executed.
-n, --nop
No operation mode. Actual execution of the essential shell commands which would be executed is suppressed.
-w, --warning
Show warning on substitution operation resulting in no content change on every file. The default is to show a warning on substitution
operations resulted in no content change on all files.
-q, --quiet
Suppress warning on substitution operation resulting in no content change.
-s, --stealth
Stealth operation. Preserve timestamp on file.
-i, --interactive
Enter interactive mode where the user has to approve each operation.
-b, --backup ext
Preserve backup of original file using file name extension ext. Default is to overwrite the original file.
-e, --exec cmd
Specify sed(1) command directly.
-f, --file cmd-file
Read sed(1) command from file.
EXAMPLE
# shell script
shtool subst -i -e 's;(c) ([0-9]*)-2000;(c) 1-2001;' *.[ch]
# RPM spec-file
%install
shtool subst -v -n
-e 's;^(prefix=).*;1 $RPM_BUILD_ROOT%{_prefix};g'
-e 's;^(sysconfdir=).*;1 $RPM_BUILD_ROOT%{_prefix}/etc;g'
`find . -name Makefile -print`
make install
HISTORY
The GNU shtool subst command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 2001 for GNU shtool. It was prompted
by the need to have a uniform and convenient patching frontend to sed(1) operations in the OpenPKG package specifications.
SEE ALSO shtool(1), sed(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-SUBST.TMP(1)
02-28-2011
