Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
I am trying to extract 'postmaster' from the following string:
PenaltyError:=554 5.7.1 Error, send your mail to postmaster@LOCALDOMAIN
using the following command:
cat /usr/share/assp/assp.cfg | grep ^PenaltyError:= | cut -d '@' -f1 | cut -f8
but it returns:
PenaltyError:=554 5.7.1 Error,... (10 Replies)
Hi,
I've a situation where,
a=xxx.yyy.zzz.txt
EXTN=`echo $a | cut -d . -f2`
Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do... (6 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Hi All-
We have a file data as below with delimiter as |#|
10|#|20|#|ABC
13|#|23|#|PBC
If I want to cut the 2nd field out of this, below command is not working as multiple pipe is causing an issue , it seems
cut -f2 -d"|#|" <file_name>
can you please help to provide the correct command... (7 Replies)
Discussion started by: sureshg_sampat
7 Replies
LEARN ABOUT DEBIAN
ruby-switch
RUBY-SWITCH(1)RUBY-SWITCH(1)NAME
ruby-switch - switch between different Ruby interpreters
USAGE
ruby-switch --list
ruby-switch --check
ruby-switch --set RUBYVERSION
ruby-switch --auto
DESCRIPTION
ruby-switch can be used to easily switch to different Ruby interpreters as the default system-wide interpreter for your Debian system.
When run with --list, all supported Ruby interpreters are listed.
When --check is passed, ruby-switch will check which Ruby interpreter is currently being used. If the settings are inconsistent -- e.g.
`ruby` is Ruby 1.8 and `gem` is using Ruby 1.9.1, ruby-switch will issue a big warning.
When --set RUBYINTERPRETER is used ruby-switch will switch your system to the corresponding Ruby interpreter. This includes, for example,
the default implementations for the following programs: ruby, gem, irb, erb, testrb, rdoc, ri.
ruby-switch --set auto will make your system use the default Ruby interpreter currently suggested by Debian.
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Displays the help and exits.
A NOTE ON RUBY 1.9.x
Ruby uses two parallel versioning schemes: the `Ruby library compatibility version' (1.9.1 at the time of writing this), which is similar
to a library SONAME, and the `Ruby version' (1.9.3 is about to be released at the time of writing).
Ruby packages in Debian are named using the Ruby library compatibility version, which is sometimes confusing for users who do not follow
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ruby-switch also uses the Ruby library compatibility version, so specifying `ruby1.9.1' might give you Ruby with version 1.9.2, or with
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Copyright (c) 2011, Antonio Terceiro <terceiro@debian.org>
This program is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by
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2011-11-20 RUBY-SWITCH(1)