Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
I am trying to extract 'postmaster' from the following string:
PenaltyError:=554 5.7.1 Error, send your mail to postmaster@LOCALDOMAIN
using the following command:
cat /usr/share/assp/assp.cfg | grep ^PenaltyError:= | cut -d '@' -f1 | cut -f8
but it returns:
PenaltyError:=554 5.7.1 Error,... (10 Replies)
Hi,
I've a situation where,
a=xxx.yyy.zzz.txt
EXTN=`echo $a | cut -d . -f2`
Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do... (6 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Hi All-
We have a file data as below with delimiter as |#|
10|#|20|#|ABC
13|#|23|#|PBC
If I want to cut the 2nd field out of this, below command is not working as multiple pipe is causing an issue , it seems
cut -f2 -d"|#|" <file_name>
can you please help to provide the correct command... (7 Replies)
Discussion started by: sureshg_sampat
7 Replies
LEARN ABOUT DEBIAN
dictfmt_index2word
DICTFMT_INDEX2WORD(1) Linux User's Manaul DICTFMT_INDEX2WORD(1)NAME
dictfmt_index2word - Creates a .word index file from a DICTD database .index file
SYNOPSIS
dictfmt_index2word [OPTIONS] [index_file]
DESCRIPTION
dictfmt_index2word creates a word index file on stdout for the index file given on stdin or the command line. A word index file indexes
each subword from the multi-word headwords of the .index file, to the underlying .dict file. A word index file is usually named <base-
name>.word, but this is not mandatory as long as the proper name is used in the dictd configuration file.
OPTIONS --help displays a usage message and exits
--locale locale
use locale for sorting the .word file. If this option is omitted, the default locale "C" is used.
index_file
the .index file to be converted.
AUTHOR
dictfmt_index2word was written by Aleksey Cheusov <vle@gmx.net>.
This manual page was written by Robert D. Hilliard <hilliard@debian.org>.
SEE ALSO dictd(8), dictfmt(1), dictfmt_index2suffix(1)LINUX January 23, 2003 DICTFMT_INDEX2WORD(1)