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Top Forums Shell Programming and Scripting Error while connecting to Oracle with Script Post 302498954 by Oracle_User on Wednesday 23rd of February 2011 12:57:13 AM
Old 02-23-2011
Error while connecting to Oracle with Script

Experts,

I am using the following Linux version:

Linux localhost.localdomain 2.6.9-22.ELsmp #1 SMP Mon Sep 19 18:32:14 EDT 2005 i686 i686 i386 GNU/Linux

and creating a ksh script with below code in it.
Code:
clear
sqlplus RIB/RIB321@RIB_LOCAL
#whenever sqlerror exit failure
#set serveroutput on size 1000000
exec entry_to_employees_result('Raja','Khan','eftgggs@gmail.com','12');
exit;

while running the above script, It connects me to the oracle database but its not executing the procedure 'entry_to_employees_result'. Then, writing EXIT manually i am getting the below mentioned error:
Code:
SQL*Plus: Release 10.2.0.1.0 - Production on Wed Feb 23 04:38:36 2011
Copyright (c) 1982, 2005, Oracle.  All rights reserved.

Connected to:
Oracle9i Enterprise Edition Release 9.2.0.1.0 - Production
With the Partitioning, OLAP and Oracle Data Mining options
JServer Release 9.2.0.1.0 - Production
SQL> exit
Disconnected from Oracle9i Enterprise Edition Release 9.2.0.1.0 - Production
With the Partitioning, OLAP and Oracle Data Mining options
JServer Release 9.2.0.1.0 - Production
./insert_to_table.ksh[14]: syntax error: `(' unexpected
[origin@localhost testdir]$


Can anyone help me out of this.

Regards
Oracle User

Last edited by Franklin52; 02-23-2011 at 03:28 AM.. Reason: Please use code tags, thank you
 

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PHP_UNAME(3)								 1							      PHP_UNAME(3)

php_uname - Returns information about the operating system PHP is running on

SYNOPSIS
string php_uname ([string $mode = "a"]) DESCRIPTION
php_uname(3) returns a description of the operating system PHP is running on. This is the same string you see at the very top of the phpinfo(3) output. For the name of just the operating system, consider using the PHP_OS constant, but keep in mind this constant will con- tain the operating system PHP was built on. On some older UNIX platforms, it may not be able to determine the current OS information in which case it will revert to displaying the OS PHP was built on. This will only happen if your uname() library call either doesn't exist or doesn't work. PARAMETERS
o $mode -$mode is a single character that defines what information is returned: o 'a': This is the default. Contains all modes in the sequence "s n r v m". o 's': Operating system name. eg. FreeBSD. o 'n': Host name. eg. localhost.example.com. o 'r': Release name. eg. 5.1.2-RELEASE. o 'v': Version information. Varies a lot between operating systems. o 'm': Machine type. eg. i386. RETURN VALUES
Returns the description, as a string. EXAMPLES
Example #1 Some php_uname(3) examples <?php echo php_uname(); echo PHP_OS; /* Some possible outputs: Linux localhost 2.4.21-0.13mdk #1 Fri Mar 14 15:08:06 EST 2003 i686 Linux FreeBSD localhost 3.2-RELEASE #15: Mon Dec 17 08:46:02 GMT 2001 FreeBSD Windows NT XN1 5.1 build 2600 WINNT */ if (strtoupper(substr(PHP_OS, 0, 3)) === 'WIN') { echo 'This is a server using Windows!'; } else { echo 'This is a server not using Windows!'; } ?> There are also some related Predefined PHP constants that may come in handy, for example: Example #2 A few OS related constant examples <?php // *nix echo DIRECTORY_SEPARATOR; // / echo PHP_SHLIB_SUFFIX; // so echo PATH_SEPARATOR; // : // Win* echo DIRECTORY_SEPARATOR; // echo PHP_SHLIB_SUFFIX; // dll echo PATH_SEPARATOR; // ; ?> SEE ALSO
phpversion(3), php_sapi_name(3), phpinfo(3). PHP Documentation Group PHP_UNAME(3)
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