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AWK Programming Problem
Post 302497212 by ctsgnb on Wednesday 16th of February 2011 02:57:13 PM
02-16-2011
" s=p=$1 OFS $2 is the same as s=p=$1 OFS $2" really ??? 
With the s=p=$1 i was just wondering if the affectation sequence was processed from right to left order but ok, this is the case so it just equivalent to p=$1 ; s=p so at the end s and p have the same value which in fact quite intuitive regarding to the notation, but i wasn't sure.
Because if the affectation would have been processed from left to right , this would have meant a rotation so that it could have been used for shifting field to the left.
But , ok i got it now ... Thx
With the s=p=$1 i was just wondering if the affectation sequence was processed from right to left order but ok, this is the case so it just equivalent to p=$1 ; s=p so at the end s and p have the same value which in fact quite intuitive regarding to the notation, but i wasn't sure.
Because if the affectation would have been processed from left to right , this would have meant a rotation so that it could have been used for shifting field to the left.
But , ok i got it now ... Thx
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LEARN ABOUT REDHAT
operator
OPERATOR(7) Linux Programmer's Manual OPERATOR(7) NAME
operator - C operator precedence and order of evaluation DESCRIPTION
This manual page lists C operators and their precedence in evaluation. Operator Associativity () [] -> . left to right ! ~ ++ -- + - (type) * & sizeof right to left * / % left to right + - left to right << >> left to right < <= > >= left to right == != left to right & left to right ^ left to right | left to right && left to right || left to right ?: right to left = += -= *= /= %= <<= >>= &= ^= |= right to left , left to right COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the latest version of this page, can be found at https://www.kernel.org/doc/man-pages/. Linux 2011-09-09 OPERATOR(7)