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Top Forums Shell Programming and Scripting If statement is not working in KSH Post 302495230 by Corona688 on Wednesday 9th of February 2011 05:41:40 PM
Old 02-09-2011
Quote:
Originally Posted by cfajohnson
The dash shell is probably the most POSIX-compliant (i.e., the most standard) shell there is, with the fewest extensions.

In what situations does the read command not work correctly?
Just 'read' by itself and no parameters throws an error message. It's the very first shell I've encountered that does that.
 

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MYSQLI_STMT_ERROR(3)							 1						      MYSQLI_STMT_ERROR(3)

mysqli_stmt::$error - Returns a string description for last statement error

       Object oriented style

SYNOPSIS
string$mysqli_stmt->error () DESCRIPTION
Procedural style string mysqli_stmt_error (mysqli_stmt $stmt) Returns a string containing the error message for the most recently invoked statement function that can succeed or fail. PARAMETERS
o $ stmt -Procedural style only: A statement identifier returned by mysqli_stmt_init(3). RETURN VALUES
A string that describes the error. An empty string if no error occurred. EXAMPLES
Example #1 Object oriented style <?php /* Open a connection */ $mysqli = new mysqli("localhost", "my_user", "my_password", "world"); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s ", mysqli_connect_error()); exit(); } $mysqli->query("CREATE TABLE myCountry LIKE Country"); $mysqli->query("INSERT INTO myCountry SELECT * FROM Country"); $query = "SELECT Name, Code FROM myCountry ORDER BY Name"; if ($stmt = $mysqli->prepare($query)) { /* drop table */ $mysqli->query("DROP TABLE myCountry"); /* execute query */ $stmt->execute(); printf("Error: %s. ", $stmt->error); /* close statement */ $stmt->close(); } /* close connection */ $mysqli->close(); ?> Example #2 Procedural style <?php /* Open a connection */ $link = mysqli_connect("localhost", "my_user", "my_password", "world"); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s ", mysqli_connect_error()); exit(); } mysqli_query($link, "CREATE TABLE myCountry LIKE Country"); mysqli_query($link, "INSERT INTO myCountry SELECT * FROM Country"); $query = "SELECT Name, Code FROM myCountry ORDER BY Name"; if ($stmt = mysqli_prepare($link, $query)) { /* drop table */ mysqli_query($link, "DROP TABLE myCountry"); /* execute query */ mysqli_stmt_execute($stmt); printf("Error: %s. ", mysqli_stmt_error($stmt)); /* close statement */ mysqli_stmt_close($stmt); } /* close connection */ mysqli_close($link); ?> The above examples will output: Error: Table 'world.myCountry' doesn't exist. SEE ALSO
mysqli_stmt_errno(3), mysqli_stmt_sqlstate(3). PHP Documentation Group MYSQLI_STMT_ERROR(3)
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