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Top Forums Shell Programming and Scripting Finding some records with sed command Post 302494328 by Aia on Monday 7th of February 2011 01:01:36 AM
Old 02-07-2011
Quote:
Originally Posted by shizik
thanks, but this file very BIG(>20 GB)
I know grep command, but it takes too much time
do you know how get these records by sed command?
I don't know what gave you the impression that sed would do a faster job than grep or awk for the same matter.

The syntax for what you want is:
Code:
sed -n '/matching_pattern/ p' filename

Which it is the same that
Code:
grep 'matching_pattern' filename

awk it is a field processor, that's what it does best and what you want.

instead of:
Code:
awk '{if($6~/(2588300|2580000|2587021)$/)print}'

I would:
Code:
awk '$6 ~ /(2588300|2580000|2587021)/' filename

The if is not necessary and the end of line $ is extra, since you want that pattern in 6th field.

Perhaps, you have to get to terms that 20Gb+ is a lot of data to process, and search takes time, regardless.

Last edited by Aia; 02-07-2011 at 02:15 AM..
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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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