02-01-2011
How to fetch a specific line from file
Hi,
I have text file in the following strucher .
The files contain hondreds of lines.
value1;value2;value3;value4
I would like to get back the line with lowest date (values4 field).
In this case its line number 3.
groupa;Listener;1;20110120162018
groupb;Database;0;20110201122641
groupc;job_q_processes;2;20101210111928
groupd;job_scheduler;0;20110201122641
Thanks
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JOIN(1) General Commands Manual JOIN(1)
NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard
input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis-
carded.
These options are recognized:
-an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-e s Replace empty output fields by string s.
-jn m Join on the mth field of file n. If n is missing, use the mth field in each file.
-o list
Each output line comprises the fields specified in list, each element of which has the form n.m, where n is a file number and m is a
field number.
-tc Use character c as a separator (tab character). Every appearance of c in a line is significant.
SEE ALSO
sort(1), comm(1), awk(1)
BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort.
The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous.
7th Edition April 29, 1985 JOIN(1)