I wanted to extract the month number from unix.
unixdev(invent) /home/odsapp/apps/CTSI
==> date
Tue Nov 11 14:42:27 EST 2008
From date command, i can get day(11), year(2008). But i need month number..
I am receiving files as test11102008.txt
My need to identify when this file is... (1 Reply)
Hi
I have a file with the following entries:
cm2363db
cm2445db
cm2618db
Is there a awk or sed command which would allow me to extract only the numbers from this file as output, so the output would look like this:
2363
2445
2618
Thanks a lot -A (4 Replies)
Hi Gurus,
I've using HPUX B.11.23 U ia64 with shell = sh.
I've been having some problem get the highest number of this script.
Actually I wanted to get the highest number from this listing (TEST123 data and based on this highest number, there will be email being sent out.
For example,... (6 Replies)
I have the following script (which I made by my self)
#!/bin/bash
# add a few empty lines to make it more legible
# add a date description on each update interval
echo "" >> /home/user/DYN_DNS_IP_change.log
echo "" >> /home/user/DYN_DNS_IP_change.log
echo "" >>... (6 Replies)
Hi Folks,
I want to use particular number as a variable output..Please find the below for scenario...
Example 1:-
Below output i want to use secondary group 9003 as a variable output
$ id -a |awk -NF '{print $3}'
groups=99(local),9003(testadmin)
Else
I want to use 2006 as a... (8 Replies)
Hi,
i want to extract a number from a statement.
03/07/14 00:58:41 CRPr::CopyTotable inserted 3501 rows into table
Now i want to assign 3501 to a variable. This number may change every time. (5 Replies)
Hi
I am on Sun os. I have data in the below format and I need to grab the number out from the string.
O/p needed:
---------- Post updated at 12:39 PM ---------- Previous update was at 12:32 PM ----------
I tried this but I am getting . at the front (14 Replies)
I have a lot of file with a lot of lines following the same pattern
the lines go like this:
alpha_9/output- -413.74928476 2.6116
and I want it to be:
9 -413.74928476 2.6116
thanks for the help (5 Replies)
Discussion started by: galboski
5 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
Please notice this option isn't related to the terminal length as in a "80 culums terminal".
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do right to left (RTL) layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter and A4. Default is A4.
Postscript points
Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch.
--bottom-margin=bm
Set bottom margin. Default is 36 postscript points.
--top-margin=tm
Set top margin. Default is 36 postscript points.
--left-margin=lm
Set left margin. Default is 36 postscript points.
--right-margin=rm
Set right margin. Default is 36 postscript points.
--gutter-width=gw
Set gutter width. Default is 40 postscript points.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)