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How to extract the number from the pattern

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# 1  
Old 10-02-2009
How to extract the number from the pattern

I have a file with the following entries:

Is there a awk or sed command which would allow me to extract only the numbers from this file as output, so the output would look like this:

Thanks a lot -A

Last edited by vgersh99; 10-02-2009 at 02:03 PM.. Reason: code tags, PLEASE!
# 2  
Old 10-02-2009
echo 'cm2363db' | sed 's/[^0-9]//g'

# 3  
Old 10-02-2009
tr -cd '[[:digit:]]\n' < FILE

# 4  
Old 10-02-2009
or with gnu grep:

grep -oE '[0-9]+' file

# 5  
Old 10-02-2009
Originally Posted by anchal_khare
or with gnu grep:

grep -oE '[0-9]+' file

That will put each set of numbers on a new line, not what the OP wants.

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