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Top Forums UNIX for Dummies Questions & Answers Passing a Shell Variable to awk Post 302491203 by Franklin52 on Thursday 27th of January 2011 02:28:57 AM
Old 01-27-2011
Quote:
Originally Posted by Gussifinknottle
Thanks for your input Franklin52. However, I need to pass it as a variable, since the program(s) I shall be executing subsequently on the input file will depend on the individual values I extract.

Thanks,
Guss.
You can use variables like this:
Code:
awk -v var1="TP" -v var2="10" -v var3="100" '
$2==var1 && $3 >= var2 && $3 <= var3' inputFile > PatternFile

This User Gave Thanks to Franklin52 For This Post:
 

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SHTOOL-TABLE.TMP(1)					      GNU Portable Shell Tool					       SHTOOL-TABLE.TMP(1)

NAME
shtool-table - GNU shtool pretty-print a field-separated list SYNOPSIS
shtool table [-F|--field-sep sep] [-w|--width width] [-c|--columns cols] [-s|--strip strip] strsepstr... DESCRIPTION
This pretty-prints a list of strings as a table. OPTIONS
The following command line options are available. -F, --field-sep sep Separate columns using sep. Default is ":". -w, --width width Width of each column. Default is 15 characters. -c, --columns cols Number of columns. Default is 3. -s, --strip strip Strip off any characters past strip. Default is 79. EXAMPLE
# shell script shtool table -F , -w 5 -c 4 "1,2,3,4,5,6,7,8,9,10,11,12" HISTORY
The GNU shtool table command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1999 for GNU shtool. SEE ALSO
shtool(1), tr(1), fmt(1), sh(1), awk(1), sed(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-TABLE.TMP(1)
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