01-02-2011
Can't sort file by size column
Hello,
I've done
ls -ls >fileout1
When I do the sort command for +4 it sorts it bu group. When I do +5 it sorts it by date. But it's skipping the file size column. Example:
rwxr-xr-x 1 Grueben sup 65 16 Sep 13:58 cdee
How can I sort it by file size? It doesn't seem to recognize it as a valid field.
Cheers
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SORT(1) General Commands Manual SORT(1)
NAME
sort - sort a file of ASCII lines
SYNOPSIS
sort [-bcdfimnru] [-tc] [-o name] [+pos1] [-pos2] file ...
OPTIONS
-b Skip leading blanks when making comparisons
-c Check to see if a file is sorted
-d Dictionary order: ignore punctuation
-f Fold upper case onto lower case
-i Ignore nonASCII characters
-m Merge presorted files
-n Numeric sort order
-o Next argument is output file
-r Reverse the sort order
-t Following character is field separator
-u Unique mode (delete duplicate lines)
EXAMPLES
sort -nr file # Sort keys numerically, reversed
sort +2 -4 file # Sort using fields 2 and 3 as key
sort +2 -t: -o out # Field separator is :
sort +.3 -.6 # Characters 3 through 5 form the key
DESCRIPTION
Sort sorts one or more files. If no files are specified, stdin is sorted. Output is written on standard output, unless -o is specified.
The options +pos1 -pos2 use only fields pos1 up to but not including pos2 as the sort key, where a field is a string of characters delim-
ited by spaces and tabs, unless a different field delimiter is specified with -t. Both pos1 and pos2 have the form m.n where m tells the
number of fields and n tells the number of characters. Either m or n may be omitted.
SEE ALSO
comm(1), grep(1), uniq(1).
SORT(1)