Evening all,
Have been trying to create the following environment variable:
${MD_SYSTEM}_ZZ_EMAIL_SUPPORT="myname@domain.com"
However when the script that contains the above is executed it returns:
ksh: MDQA_ZZ_EMAIL_SUPPORT=myname@domain.com: not found
Is what I'm trying to do... (2 Replies)
Bit of a newbie :D with regard to unix scripting and need some advice. Hopefully someone can help with the following:
I have a predefined set of variables as follows:
AAA_IP_ADD=1.1.1.1
BBB_IP_ADD=2.2.2.2
I have a funnction call which retrieves a value into $SUPPLIER which would be... (3 Replies)
Hi All,
I have the below scenario:
A file test.cfg with three fields>>
DATA1 DATA2 DATA3
In the script I need to assign each of the fields to variables. The number of fields will not be constant (this case we have three). Im trying to do something like this:
NUM=1
OUT_DAT_NO=3
... (4 Replies)
I found one post in another site with a solution for my problem
the below solution should explain what I want.
#!/bin/sh
first="one"
second="two"
third="three"
myvar="first"
echo ${!myvar}
But this gives error 'bad substitution'
System info
SunOS sundev2 5.9... (3 Replies)
Hi all,
I’m very new to UNIX programming. I have a question on dynamic variable
1. I’m having delimited file (only one row). First of all, I want to count number of columns based on delimiter. Then I want to create number of variables equal to number of fields.
Say number of... (5 Replies)
QUERY IN BRIEF
Listing the query in short
#! /bin/csh -f
#say i have invoked the script with two arguments : a1 and 2
set arg = $1 # that means arg = a1
echo "$arg" #it prints a1
#now what i want is:
echo "$a1"
#it will give error message :a1 undefined.
#however what i need is that the... (2 Replies)
Hi guys.
i have a requirment as below.
I have a scripts which perform for loop
for i in /backup/logs -- it will give all the logs file
SC_RIO_RWVM_20120413064217303.LOG
SC_RIO_RWXM_20120413064225493.LOG
SC_RIO_RXXM_20120413064233273.LOG
...
do
open script.sh ---- in this file... (3 Replies)
I have a small program which needs to pass variable dynamically to form the name of a second variable whose value wil be passed on to a third variable.
***************** Program Start ******************
LOC1=/loc1
PAT1IN=/loc2
PAT2IN=/loc3
if ; then
for fpattern in `cat... (5 Replies)
My Code :
--------------------------------------------
#!/bin/bash
for i in `echo server1 server2`
do
eval ${i}_name = "apache"
echo ${i}_name
done
--------------------------------------------
Current output :
>./test.sh
./test.sh: line 5: server1_name: command not found... (3 Replies)
Hello,
I'm trying to build a small script to store a command into a dynamic variable, and I have trouble assigning the variable.
#!/bin/bash
declare -a var1array=("value1" "value2" "value3")
var1arraylength=${#var1array}
for (( i=1; i<${var1arraylength}+1; i++ ));
do
mkdir... (7 Replies)
Discussion started by: alex2005
7 Replies
LEARN ABOUT CENTOS
alter_group
ALTER GROUP(7) PostgreSQL 9.2.7 Documentation ALTER GROUP(7)NAME
ALTER_GROUP - change role name or membership
SYNOPSIS
ALTER GROUP group_name ADD USER user_name [, ... ]
ALTER GROUP group_name DROP USER user_name [, ... ]
ALTER GROUP group_name RENAME TO new_name
DESCRIPTION
ALTER GROUP changes the attributes of a user group. This is an obsolete command, though still accepted for backwards compatibility, because
groups (and users too) have been superseded by the more general concept of roles.
The first two variants add users to a group or remove them from a group. (Any role can play the part of either a "user" or a "group" for
this purpose.) These variants are effectively equivalent to granting or revoking membership in the role named as the "group"; so the
preferred way to do this is to use GRANT(7) or REVOKE(7).
The third variant changes the name of the group. This is exactly equivalent to renaming the role with ALTER ROLE (ALTER_ROLE(7)).
PARAMETERS
group_name
The name of the group (role) to modify.
user_name
Users (roles) that are to be added to or removed from the group. The users must already exist; ALTER GROUP does not create or drop
users.
new_name
The new name of the group.
EXAMPLES
Add users to a group:
ALTER GROUP staff ADD USER karl, john;
Remove a user from a group:
ALTER GROUP workers DROP USER beth;
COMPATIBILITY
There is no ALTER GROUP statement in the SQL standard.
SEE ALSO GRANT(7), REVOKE(7), ALTER ROLE (ALTER_ROLE(7))
PostgreSQL 9.2.7 2014-02-17 ALTER GROUP(7)