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Top Forums Shell Programming and Scripting script to check for a directory in /home for all users Post 302484348 by methyl on Thursday 30th of December 2010 04:43:27 PM
Old 12-30-2010
Thank you for making the question clear. Sorry if I was a bit abrupt earlier.

Quote:
3. mount a separate directory that resided on a different partition at the mount point that has just been created for all users.
Like frans I am having difficulty understanding item 3 in a unix context.

The Linux "mount" command is used to mount a filesystem on a mountpoint.
A mountpoint is an empty directory which acts as a pointer to the filesystem.
We would normally mount the filesystem on system startup using parameters in one line of "fstab". I can't see a reason to make this dynamic.

As frans correctly deduced, the conventional approach in unix is to use a soft link (see "man ln") to point a directory under a user's home directory to a directory in a filesystem which is under a different mountpoint from the user's home directory.
I am unclear whether there is to be one common directory for all users or multiple individual directories.

Quote:
1. check if a given directory is present in /home of all users
2. create the directory if it is not present to act as a mount point
If we are using soft links, items 1 and 2 only need to be done once for existing accounts and then as required when a new account is created.


(I had not seen posts #5 and #6 before eventually posting).
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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