Sponsored Content
Top Forums UNIX for Dummies Questions & Answers find a word in a file, plus the next 6 characters? Post 302484032 by verdepollo on Wednesday 29th of December 2010 11:19:26 AM
Old 12-29-2010
Like this?

Code:
sed 's/.*\(word1_a[0-9][0-9][0-9][0-9][0-9][0-9]\).*/\1/' infile

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

find a word in a file, and change a word beneath it ??

Hi all, I have a file with lines written somewhat like this. aaaa ccc aa linux browse = no xssxw cdcedc dcsdcd csdw police dwed dwd browse = no cdecec (2 Replies)
Discussion started by: vikas027
2 Replies

2. Shell Programming and Scripting

Find Exact word in file

Hi ALL, I want to search one string “20 “ i.e 20 with space. But my file where I am searching this “20 “ contain some data like 120 before image file truncated 220 Reports section succeeded 20 Transaction database .prd stopped 220 Reports section completed. When I search for the... (5 Replies)
Discussion started by: Jeevan Salunke
5 Replies

3. Shell Programming and Scripting

find replace a pattern and following characters in a word

Suppose that I have a string "one:#red two:#yellow three:#gr'een four:#blu^e" and I want to replace the pattern :# and the following characters in the word with nothing. The output string should look "one two three four" How can I do this with sed. Some points to consider (a) the last word in... (1 Reply)
Discussion started by: superuser84
1 Replies

4. Shell Programming and Scripting

Find word in file then get following characters

Hello, I have several xml files from which I want to find and return a particular string I want to locate the InId="00000008". Now that is inlcuded within a tag and ofcourse the number is different every time this is what I came up with given that after greping the line that contains the... (6 Replies)
Discussion started by: TasosARISFC
6 Replies

5. Shell Programming and Scripting

How to find a particular word from a file

Hello Experts, I have to count the word like "RESULT_CODE: : -6" from the multiple files names like req.result_2_vqx-71144750.log for a particular date. Lets suppose the date is 10 OCT 2011. How I can do it with a single command in Solaris environment. Reagrds Oracle User (8 Replies)
Discussion started by: Oracle_User
8 Replies

6. UNIX for Dummies Questions & Answers

Find EXACT word in files, just the word: no prefix, no suffix, no 'similar', just the word

I have a file that has the words I want to find in other files (but lets say I just want to find my words in a single file). Those words are IDs, so if my word is ZZZ4, outputs like aaZZZ4, ZZZ4bb, aaZZZ4bb, ZZ4, ZZZ, ZyZ4, ZZZ4.8 (or anything like that) WON'T BE USEFUL. I need the whole word... (6 Replies)
Discussion started by: chicchan
6 Replies

7. UNIX for Dummies Questions & Answers

Find word in a large file

Hi all I am working on disallowing users to use easy passwords in pam.d setting on RHEL 5.7 and SuSe 11, and I was hoping to add more words into the current cracklib dict, so I use "echo" command to append new words into the file I dont want to add the same words into the dict, I think I... (2 Replies)
Discussion started by: hedkandi
2 Replies

8. Shell Programming and Scripting

Search for the word and exporting 35 characters after that word using shell script?

I have a file input.txt which have loads of weird characters, html tags and useful materials. I want to display 35 characters after the word description excluding weird characters like $$#$#@$#@***$# and without html tags in the new file output.txt. Help me. Thanx in advance. My final goal is to... (11 Replies)
Discussion started by: sachit adhikari
11 Replies

9. Shell Programming and Scripting

Search for the word and exporting 35 characters after that word using shell script

I have a file input.txt which have loads of weird characters, html tags and useful materials. I want to display 35 characters after the word "description" excluding weird characters like $&lmp and without html tags in the new file output.txt. Help me. Thanx in advance. I have attached the input... (4 Replies)
Discussion started by: sachit adhikari
4 Replies

10. Shell Programming and Scripting

Count characters in a csv file and add an word.

Hello, I want to add a sentence to "post column" those who are only less than 30 characters.Thank you very much for your help. "category","title","post" "Z","Zoo","test 54325 test 45363mc." "Z","Zen","rs2w3rsj 2d342dg 2d3s4f23 d23423s23h 2s34s2423g ds232d34 2342." "Z","Zet","test4444... (3 Replies)
Discussion started by: hoo
3 Replies
PREG_QUOTE(3)								 1							     PREG_QUOTE(3)

preg_quote - Quote regular expression characters

SYNOPSIS
string preg_quote NULL (string $str, [string $delimiter]) DESCRIPTION
preg_quote(3) takes $str and puts a backslash in front of every character that is part of the regular expression syntax. This is useful if you have a run-time string that you need to match in some text and the string may contain special regex characters. The special regular expression characters are: . + * ? [ ^ ] $ ( ) { } = ! < > | : - PARAMETERS
o $str - The input string. o $delimiter - If the optional $delimiter is specified, it will also be escaped. This is useful for escaping the delimiter that is required by the PCRE functions. The / is the most commonly used delimiter. RETURN VALUES
Returns the quoted (escaped) string. CHANGELOG
+--------+--------------------------------+ |Version | | | | | | | Description | | | | +--------+--------------------------------+ | 5.3.0 | | | | | | | The - character is now quoted | | | | +--------+--------------------------------+ EXAMPLES
Example #1 preg_quote(3) example <?php $keywords = '$40 for a g3/400'; $keywords = preg_quote($keywords, '/'); echo $keywords; // returns $40 for a g3/400 ?> Example #2 Italicizing a word within some text <?php // In this example, preg_quote($word) is used to keep the // asterisks from having special meaning to the regular // expression. $textbody = "This book is *very* difficult to find."; $word = "*very*"; $textbody = preg_replace ("/" . preg_quote($word, '/') . "/", "<i>" . $word . "</i>", $textbody); ?> NOTES
Note This function is binary-safe. SEE ALSO
PCRE Patterns, escapeshellcmd(3). PHP Documentation Group PREG_QUOTE(3)
All times are GMT -4. The time now is 12:51 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy