12-28-2010
sed question
Hi,
I am trying to write a script which will do the following:
1. edit the cron entries for specific scripts.
2. comment out the cron entries
3. make them out of schedule.
4. do some other operation.
4. remove the comments from crontab.
5. reschedule the scripts.
I believe we can use 'sed' statement to do this entire operation in one line, but i am a beginner in sed.
Please let me know if you have any ideas on this.
-Sam
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
Is there any way to traverse the file once and look for the following conditions in one sweep instead of going over the file 3 times with different search criteria......
sed -n '/^ORA-07445/ p' /tmp/t$$ > ${OERRFILE}
sed -n '/^ORA-00600/ p' /tmp/t$$ >> ${OERRFILE}
... (1 Reply)
Discussion started by: YS2002
1 Replies
2. Shell Programming and Scripting
hello there, I have a sed question.
I have a file (temp.srv), in it it has
v1_host1
v2_host2
And I have another file (temp2.srv), in it is has
v1_host3_date
v1_host1
v2_host2
v2_host4_date
v3_host5_date
I had used a script to remove the name from temp2.srv base on the name inside... (3 Replies)
Discussion started by: ahtat99
3 Replies
3. Shell Programming and Scripting
Hi,
When deleting lines using sed, as i understand the lines are redirected to the standard output. What i'm unclear about is how to actually modify the file?
If I write the command sed '1,2d' test it will display lines one and 2 onto the screen however the file is not modified? I think my... (5 Replies)
Discussion started by: c19h28O2
5 Replies
4. Shell Programming and Scripting
Hi, :)
can any body explain the following statement
sed 's/\(\)- ]//g'
cheers
RRK (3 Replies)
Discussion started by: ravi raj kumar
3 Replies
5. Shell Programming and Scripting
I have a file that conatins following info
Policy1=U|guestRoom=test1idCode=5(1):!:Amenity2=U|RoomId=testrma=4(1):!:|
GuestRoomAmenity1=U|guestRoomId=testguest1id^rmaCode=5(1):!:|
I need it to look like this
Policy1=U|guestRoom=test1idCode
Amenity2=U|RoomId=testrmaCode... (2 Replies)
Discussion started by: arushunter
2 Replies
6. UNIX for Dummies Questions & Answers
How would I use sed to print everything on the line after the regular expresion?
I have a configuration file setting several variables.
cfg.dat
DDB = cpptest
SUDBNAME = sucpptestdb
host = cpptest
Example
I want to search for the regular expresion 'SUDBNAME =' and print everything on... (3 Replies)
Discussion started by: orahi001
3 Replies
7. Shell Programming and Scripting
Write a sed script to extract the year, rank, and stock for the most recent 10 years available in the file top10_mktval.csv, and output in the following format:
------------------------------
YEAR |RANK| STOCK
------------------------------
2007 | 1 | Exxon... (1 Reply)
Discussion started by: beibeiatNY
1 Replies
8. Shell Programming and Scripting
hi
i have a file with this line:
variable=/export/home/oracle
I want to change the file so that the path is replaced with the value of another variable
var2=/tmp/anything.
how to do this in sed?
thx (4 Replies)
Discussion started by: melanie_pfefer
4 Replies
9. Shell Programming and Scripting
I need to replace the numbers with a new string.
How can I give a wildcard for the different # of numbers
sed '/abcdef/s/abcdef=*/abcdef=999999/'<foo>foo1
From: To:
abcdef=1234 abcdef=999999
abcdef=12345 abcdef=999999
abcdef=123456... (10 Replies)
Discussion started by: beppler
10 Replies
10. UNIX for Dummies Questions & Answers
I am trying to write a script that will take an input text file in the format
person: place: phonenumber;
person: place: phonenumber;
person: place: phonenumber;
...
and output it using sed too:
Name ######## Location ######### Phone Number... (1 Reply)
Discussion started by: jmack56
1 Replies
cron(8) System Manager's Manual cron(8)
NAME
cron - The system clock daemon
SYNOPSIS
/usr/sbin/cron
DESCRIPTION
The cron daemon runs shell commands at specified dates and times. Commands that are to run according to a regular or periodic schedule are
found within the crontab files. Commands that are to run once only are found within the at files. You submit crontab and at file entries
by using the crontab and at commands. Because the cron process exits only when killed or when the system stops, only one cron daemon
should exist on the system at any given time. Normally, you start the cron daemon from within a run command file.
During process initialization and when cron detects a change, it examines the crontab and at files. This strategy reduces the overhead of
checking for new or changed files at regularly scheduled intervals. The cron command creates a log of its activities. The cron daemon
must be started from the system startup scripts because it must begin execution without a login user ID set. The cron daemon starts each
job with the following process attributes stored with the job by the invoking process: Login user ID Effective and real user IDs Effective
and real group IDs Supplementary groups
It also establishes the following attributes from the authentication profile of the account associated with the login user ID of the invok-
ing process: Audit control and disposition masks Kernel authorizations
DIAGNOSTICS
The at and batch programs will refuse to accept jobs submitted from processes whose login user ID is different from the real user ID.
FILES
Specifies the command path. Main cron directory Directory containing the crontab files. List of allowed users. List of denied users His-
tory information for cron Queue description file for at, batch, and cron
RELATED INFORMATION
Commands: at(1), crontab(1), rc0(8), rc2(8), rc3(8)
Files: queuedefs(4) delim off
cron(8)